How do I calculate the coefficient of friction in a static friction problem?

Click For Summary

Homework Help Overview

The discussion revolves around calculating the coefficient of static friction in a problem involving two blocks, A and B, with given weights and tension. The scenario includes friction only between the two blocks, while block A is on a ramp without friction. Participants are examining the forces acting on the blocks and their relationships according to Newton's laws.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are discussing the forces acting on blocks A and B, questioning the correctness of their diagrams and the relationships between the normal forces and friction. Some express a desire to understand the physics behind the problem rather than just finding the coefficient of friction.

Discussion Status

Some participants have provided guidance regarding the forces and their relationships, noting that the normal forces must be equal and opposite. There is a recognition of the importance of static friction and the conditions under which it applies, but no consensus on the final values or methods has been reached.

Contextual Notes

Participants are working under the assumption that block A is at the verge of slipping, which affects the calculations of the coefficient of friction. There is also a mention of confusion regarding the forces acting on the blocks, particularly the normal forces.

Pysics86
Messages
3
Reaction score
0
Member advised to use the homework template for posts in the homework sections of PF.
Hi all,
I have problem to solve this question:

2iiwydi.jpg

Wb=150N
Wa=50N
T=150N
alph =?
µ =?
- There is friction between A and B only(Between A and the ramp there isn't).
- A and B not moving(first Newton's law).

3. I tried to solve as:
kcx8gk.jpg


But the answer is wrong, can anyone help me please, and explain where is the problem?

Regards Jack.
 
Physics news on Phys.org
Pysics86 said:
Hi all,
I have problem to solve this question:

2iiwydi.jpg

Wb=150N
Wa=50N
T=150N
alph =?
µ =?
- There is friction between A and B only(Between A and the ramp there isn't).
- A and B not moving(first Newton's law).

3. I tried to solve as:
kcx8gk.jpg


But the answer is wrong, can anyone help me please, and explain where is the problem?

Regards Jack.
What is your answer?
 
ehild said:
What is your answer?
The correct anser is Miu=0.25
My answer is 0.43.
 
Pysics86 said:
The correct anser is Miu=0.25
My answer is 0.43.
How did you get it?
 
By writing the forces as i the diagram forces, did the diagram, i don't care about the final answer and don't care about solving and finding the Miu, what i want to know is if the forces are right as the diagram or not, if not what is the problem, in other world i want to understand the physics not from the question from who understand physics and can explain.
 
Hi Physics86. Welcome to Physics forums. It looks like your diagrams are correct. The N? in diagram for A would be equal to Nb because those forces have to be equal and opposite. I worked through the problem and got μ = 0.25.
 
Pysics86 said:
By writing the forces as i the diagram forces, did the diagram, i don't care about the final answer and don't care about solving and finding the Miu, what i want to know is if the forces are right as the diagram or not, if not what is the problem, in other world i want to understand the physics not from the question from who understand physics and can explain.
You need to collect the forces acting on block A. You have some confusion here, as there is normal force from the ramp (Na) and there is normal force from B acting on A, that can be the blue vector N?.
The forces acting on B are correct, taking in mind that the normal force Nb is the force exerted by A, and according to Newton's Third Law, it is equal in magnitude to N?.
You need to use the correct magnitudes to get the angle alpha. Remember, the friction is static, so F≤μN, and N is the magnitude of the normal force between A and B.
 
ehild said:
Remember, the friction is static, so F≤μN
F≤μN. That is an important point. I should have pointed out that, although it wasn't stated, I assumed that one of the conditions of the problem was that block A was just at the point where it was going to slip. In that case, F would be equal to μN (F=μN). Otherwise - if that was not a condition of the problem - you would not be able to calculate μ.
 

Similar threads

  • · Replies 20 ·
Replies
20
Views
2K
Replies
7
Views
2K
Replies
43
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 15 ·
Replies
15
Views
1K
Replies
6
Views
3K
Replies
4
Views
1K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
6
Views
1K
  • · Replies 5 ·
Replies
5
Views
3K