How do I calculate the enthalpy change for this reaction?

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SUMMARY

The enthalpy change for the combustion of methane can be calculated using the formula: mass x specific heat capacity x change in temperature. In this case, burning 90 cm³ of methane raises the temperature of 100 cm³ of water from 20.0°C to 50.0°C, resulting in an enthalpy change of -12.54 kJ. The calculation is based on the specific heat capacity of water, which is 4.18 J/g°C, and the mass of water, which is derived from its volume. The enthalpy of combustion is defined as the change in enthalpy of the total reacting system.

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  • Understanding of thermodynamics concepts, specifically enthalpy changes.
  • Knowledge of specific heat capacity and its application in calorimetry.
  • Familiarity with the properties of water, including its density and specific heat capacity.
  • Basic skills in performing unit conversions, particularly between cm³ and grams.
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  • Learn about calorimetry techniques for measuring heat changes in reactions.
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Chemistry students, educators, and anyone involved in thermodynamics or calorimetry who seeks to understand the calculation of enthalpy changes in chemical reactions.

L²Cc
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When 90cm^3 of methane is burned, the heat produced is used to raise the temperature of 100 cm^3 of water from 20.0°C to 50.0C. Calculate the enthalpy change for the reaction.

I'm not getting the same answer as the textbook...Please tell me whether my method is correct

All you do here is use the formula mass x specific heat capacity x change in temp. So,
the enthalpy change would be -(100/1000) x (4.18) x (30) = -12.54 KJ ?
 
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1. For questions of this kind, please use the Homework & Coursework subforum.

2. You've found the heat produced in burning 90cc of methane. How is the enthalpy of combustion defined?
 
the change in enthalpy of the total reacting system
 

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