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marellasunny

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## Homework Statement

Fuel general formula: [itex]C_x H_y O_z[/itex]

How do I calculate the mass proportion of oxygen in the air participating in the following reaction [itex]\xi_{O_2,air}[/itex]?

$$C_x H_y O_z+(x+\frac{y}{4}-\frac{z}{2}).O_2 \rightarrow xCO_2+\frac{y}{2}H_2O$$

## Homework Equations

Mass proportion of oxygen in fuel:

$$Oxygen=\frac{M_{oxygen}}{M_{fuel}} .z $$

M-molecular weight

z- stoichiometric coefficient

## The Attempt at a Solution

The number of moles in the air would be:[itex](x+\frac{y}{4}-\frac{z}{2})[/itex]So,$$ \xi_{O_2,air}=(x+\frac{y}{4}-\frac{z}{2}) * \frac{M_{O2}}{M_{air/fuel?}}

$$

Is this correct? Is the mass proportion calculated above EQUAL to the stoichiometric air requirement?

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