How Do I Calculate the Partial Sum of an Alternating Series?

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SUMMARY

The discussion focuses on calculating the partial sum of an alternating series, specifically using the series defined by the formula \sum_{n=1}^{\infty}nx^n=\frac{x}{(x-1)^2}. The user successfully computed a partial sum of 0.10969 using 4 terms, ensuring the error was less than 0.0001. The series evaluated at x = -\frac{1}{11} results in - \frac{11}{144}, demonstrating the application of derivatives in series summation.

PREREQUISITES
  • Understanding of alternating series and convergence criteria
  • Familiarity with geometric series and their derivatives
  • Basic knowledge of error estimation in numerical methods
  • Proficiency in calculating partial sums of series
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  • Explore the concept of convergence in alternating series
  • Learn about error bounds in numerical series calculations
  • Study the application of derivatives in series summation
  • Investigate other methods for calculating partial sums, such as the Euler-Maclaurin formula
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Mathematicians, students studying calculus, and anyone interested in numerical analysis and series convergence techniques.

Nick_L
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Can anyone help me out with calculating the partial sum of an alternating series? For example, how would I find the sum correct to 4 decimal places of:

CalcProblem.gif


What I tried was finding how many terms it would take the have an error that was < .0001 then found the sum with that many terms... I got 0.10969 as the partial sum using 4 terms.
 
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Note that

[tex]\sum_{n=1}^{\infty}nx^n=\frac{x}{(x-1)^2}[/tex]

which can be obtained from the geometric series by computing the derivative and multiplying by x. Hence

[tex]\sum_{n=1}^{\infty}n(-\frac{1}{11})^n=-\frac{11}{144}[/tex]
 

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