How do I calculate the period of a wave using frequency and time increments?

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Homework Help Overview

The discussion revolves around calculating the period of a wave using its frequency and time increments. The original poster presents a scenario involving a wave plotted on a time scale with specific increments and wavelengths.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore how to derive the period from the given time increments and wavelengths, questioning the necessity of calculating frequency first. There are discussions about unit consistency and direct readings from the graph.

Discussion Status

Participants are actively engaging with the problem, offering different perspectives on how to approach the calculation of the period. Some suggest that the period can be directly read from the graph without needing to calculate frequency first, while others express confusion regarding their calculations and the relationship between period and frequency.

Contextual Notes

The original poster's calculations and understanding of the relationship between period and frequency are under scrutiny, with emphasis on ensuring correct unit dimensions and the interpretation of the graph.

StotleD
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:cry: Let' say you have a wave plotted out on a time scale. Each increment on the line is 675 ms. There are 5 increments between each wavelength. How would I find the frequency so that I can solve for the wave's period using:

Period = 1/Hz
 
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What's the problem? Just read the scale. The period is the number of seconds it takes for one wavelength to pass by right? There are 5 increments in one wavelength and 1 increment is 675 ms, so how many seconds for one wavelength?
 
The problem is I get 2.96E-4 when I multiply 675*5 then divide 1 by that. I must be doing it wrong
 
Why divide if you need the period? Also, check your units (dimensions). Period has the dimension of time, so it's measured in seconds.
 
StotleD : What Galileo is telling you is that you can directly read the period off the scale. You do not have to find the frequency and then invert it.
 
Period = 1/Hz
 
ok, thanks
 
StotleD said:
:cry: Let' say you have a wave plotted out on a time scale. Each increment on the line is 675 ms. There are 5 increments between each wavelength. How would I find the frequency so that I can solve for the wave's period using:

Period = 1/Hz
Code:
[FONT=Courier New]
                x               
              x   x
            x       x 
          x           x           x
                        x       x      
                          x   x
                            x
          |<--------------------->| 
           5x(675 ms) = The Period (directly from graph)

           Frequency = 1/(Period) = 1/(5x(675 ms))
           Period = 1/(Frequency) = 1/1/(5x(675 ms)) = (5x(675 ms)) AGAIN!
 

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