How do I convolve delta functions in Fourier transform calculations?

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SUMMARY

The discussion centers on finding the Fourier transform of the product Cos(10t)sin(t) by utilizing convolution of delta functions. Participants highlight the importance of simplifying the trigonometric expression using the half sum difference identities, resulting in the equation Cos(10t)sin(t) = 1/2 (sin(11t) - sin(9t). The key takeaway is that convolving delta functions translates to adding frequency shifts, which simplifies the Fourier transform calculations significantly.

PREREQUISITES
  • Understanding of Fourier transforms
  • Familiarity with trigonometric identities, specifically half sum difference identities
  • Knowledge of delta functions and their properties in signal processing
  • Basic skills in convolution operations
NEXT STEPS
  • Study the properties of delta functions in Fourier analysis
  • Learn about convolution in the context of signal processing
  • Explore advanced trigonometric identities and their applications in Fourier transforms
  • Investigate the implications of frequency shifts in signal processing
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Students and professionals in signal processing, electrical engineering, and applied mathematics who are working with Fourier transforms and convolution techniques.

jackdaniel
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Hi everyone, I need help finding the Fourier transform of Cos(10t)sin(t)

i know that i need to find the transform of cos and sin and then convolve them, but i m not sure how to convolve delta function. I would really appreciate any helps.
 
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No it's better to do it by simplifying the trig expression first using the "half sum difference" identities.

That is, cos(10t)sin(t) = 1/2 ( sin(11t) - sin(9t) )
 
thanks, the way you described made it a lot easier. By using your method I realized that convolving delta functions is simply adding the frequency shifts.

thanks
 

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