How do I correctly evaluate <x^2> for a particle in a one-dimensional box?

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SUMMARY

The evaluation of for a particle in a one-dimensional box of length L involves using the formula = (2/L)[(L^3/24)-(L^3/4n^2*pi^2)cos(n*pi)]. For n=1, the correct result is (L^2/12)+(L^2/(2*pi^2)), but this was initially marked incorrect. The correct evaluation for n=2 yields (L^2/12)-(L^2/(8*pi^2)), which aligns with the assignment's expectations. The discrepancy in the first evaluation was resolved by rechecking the calculations.

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Homework Statement



Consider a particle in an infinite one-dimensional box that has a length L and is centered at the origin. (Use h for Planck's constant, n, and L, as necessary.) Evaluate <x^2> for <x^2> at n=1.

Homework Equations



<x^2>= (2/L)[(L^3/24)-(L^3/4n^2*pi^2)cos(n*pi)]

The Attempt at a Solution



I used this formula and got the answer (L^2/12)+(L^2/(2*pi^2)). My assignment is telling me this is incorrect. I took the same approach for the second part of my homework asking for this when n=2, and I got (L^2/12)-(L^2/(8*pi^2)) which it says is correct. I cannot figure out why my first answer is not correct as well. Any help would be much appreciated.
 
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Sorry. Just figured it out.
 

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