How do I draw a displacement-distance graph for waves?

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To draw a displacement-distance graph for a transverse wave, it's essential to understand that no energy is lost, and the apparent velocity of the wave is provided. By applying the definition of velocity, the phase shift can be calculated after a specific time interval, in this case, 0.05 seconds. The calculation yields a shift of 0.60 meters, indicating that the graph has indeed shifted by this distance. This understanding confirms the relationship between velocity, displacement, and time in wave motion. The discussion emphasizes the importance of these principles in accurately representing wave behavior.
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I really need help with drawing displacement-distance graph for waves. The question is in the attached file. It is Q9 c. Thank you very much.:cry:
 

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Hey there!

Well, this is a transverse wave and they tell you that no energy is lost or anything like that, and also they give you the apparent velocity of the wave. Perhaps using the definition of velocity will give you the phase shift of this graph after .05 seconds?
$$V = \frac {ds}{dt} \Rightarrow Vt = s$$
 
Rellek said:
Hey there!

Well, this is a transverse wave and they tell you that no energy is lost or anything like that, and also they give you the apparent velocity of the wave. Perhaps using the definition of velocity will give you the phase shift of this graph after .05 seconds?
$$V = \frac {ds}{dt} \Rightarrow Vt = s$$
I got 0.60 as the answer, does this indicate that the graph has shifted 0.60m as a result??:confused:
 
LXX said:
I got 0.60 as the answer, does this indicate that the graph has shifted 0.60m as a result??:confused:

Yup! Same graph, shifted .6 meters.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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