MHB How Do I Find a Point on a Curve with a Specific Slope?

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To find a point P on the curve y = sqrt{x} where the slope of the line through P and (1, 1) is 1/4, use the slope formula with the points (1, 1) and (x, sqrt{x}). The slope formula is (sqrt{x} - 1) / (x - 1) = 1/4. Solving this equation will yield the specific x-coordinate for point P. The slope-intercept formula is not necessary for this problem. The focus should remain on applying the slope formula correctly to determine the desired point on the curve.
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Find a point P on the curve y = sqrt{x} such that the slope of the line through P and (1, 1) is 1/4.

Must I use the slope-intercept formula here?
 
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RTCNTC said:
Find a point P on the curve y = sqrt{x} such that the slope of the line through P and (1, 1) is 1/4.

Must I use the slope-intercept formula here?

Just the slope formula, with the points (1, 1) and $\displaystyle \begin{align*} \left( x, \sqrt{x} \right) \end{align*}$.
 
Prove It said:
Just the slope formula, with the points (1, 1) and $\displaystyle \begin{align*} \left( x, \sqrt{x} \right) \end{align*}$.

I can take it from here.
 

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