How do I find an isomorphism between Sn+m and Zn x Zm?

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SUMMARY

The discussion focuses on finding an isomorphism between a subgroup of the symmetric group Sn+m and the direct product Zn x Zm. It is established that Sn+m is generally not isomorphic to Zn x Zm, but specific cases can be analyzed, such as when n and m are both equal to 2. The key takeaway is that if two subgroups H and K of a group G have a trivial intersection and commute, then the subgroup HK is isomorphic to H x K.

PREREQUISITES
  • Understanding of group theory concepts, specifically symmetric groups.
  • Familiarity with subgroup properties and isomorphisms.
  • Knowledge of direct products in algebra.
  • Basic experience with mathematical notation and terminology.
NEXT STEPS
  • Study the properties of symmetric groups, particularly Sn+m.
  • Learn about subgroup structures and their isomorphisms in group theory.
  • Explore the concept of trivial intersections and commutativity in groups.
  • Investigate specific cases of isomorphisms between subgroups of Sn+m and direct products.
USEFUL FOR

This discussion is beneficial for mathematicians, particularly those specializing in abstract algebra, as well as students studying group theory and its applications.

clkt
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How do I find an isomorphism between Sn+m and Zn x Zm? provided n,m are not relatively prime? Thanks.
 
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I dunno, place an ad in the classifieds, put up posters, etc. Or maybe start by defining what you even mean by Sn+m, because in the standard notation, Sn+m is a group that's generally not isomorphic to Zn x Zm. Also, post this in the homework section, follow the guidelines for posting homework, and when you start a new thread in the homework section, use the template that will be given to you.
 
Hi, this isn't exactly a homework question... Anyways, rereading my question again, I made a mistake. It should be how do I find an isomorphism between A SUBGROUP in Sn+m and Zn x Zm. If it is specific cases like n,m = 2,2 I can figure it out. But how do I figure out a general form for the isomorphism?
 
If there are two subgroups H and K of a group G such that the intersection of H and K is trivial and hk=kh for all h in H, k in K, then the subgroup HK is isomorphic to HxK.
 
ah, thanks, I think I have it figured out now!
 

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