# How do I find the distance traveled if I know the acceleration and time?

## Main Question or Discussion Point

so if A is the acceleration
and T is time
and D is distance
then

D = A * T^2

right????

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berkeman
Mentor
berkeman
Mentor
I was looking for a quick check to make sure i'm right... so yes or no?
Please look at the link. The answer is right there in a big box on the front page.

Sry bud you just sent me a link to a page that contains an HTML frame. go ahead and try that link out for yourself and see. It'll just show the home page.

berkeman
Mentor
Sry bud you just sent me a link to a page that contains an HTML frame. go ahead and try that link out for yourself and see. It'll just show the home page.
Oopsies. I didn't realize the link didn't follow me down a couple of click levels. I'll have to figure out how to fix that.

In the mean time, just click on Mechanics, and then on Velocity & Acceleration.

Does that work okay?

so if A is the acceleration
and T is time
and D is distance
then

D = A * T^2

right????
Nope, it's (A *T^2 )/2

So 9 seconds and 32 f/s (1g) would cover about one quarter mile, 1320 feet.
32*81=2592, divide by 2=1296 feet. A true quarter mile would be about 9.08 seconds.

73 Berkeman, AI3N here. 2 meters, 70 cm, 20/30/40/80 voice mainly. Antenna blew down, need one of those air powered potato guns to get the dipole back in the trees!

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