How do I find the scale factor of cosmological constant?

Click For Summary
SUMMARY

The discussion focuses on calculating the scale factor of the cosmological constant and its implications for the universe's evolution. Key equations include the density relationships for dust, curvature, and vacuum, specifically ##\rho \propto a^{-3}## for dust and ##\rho_E = \frac{\Lambda c^2}{4 \pi G}## for the energy density associated with the cosmological constant. The Raychauduri Equation is utilized to derive the conditions for a static solution, emphasizing the interplay between density, pressure, and curvature in cosmological models. The analysis concludes that the universe's evolution is dominated by curvature in late times.

PREREQUISITES
  • Understanding of the Raychauduri Equation in cosmology
  • Familiarity with the concepts of dust, curvature, and vacuum energy densities
  • Knowledge of the relationship between scale factor and time in cosmological models
  • Basic grasp of integral calculus for distance calculations in curved spacetime
NEXT STEPS
  • Study the implications of the cosmological constant on universe expansion
  • Learn about the Friedmann equations and their role in cosmological dynamics
  • Explore the concept of critical density and its significance in cosmology
  • Investigate the effects of different curvature parameters on cosmic evolution
USEFUL FOR

Astronomers, cosmologists, and physics students interested in the dynamics of the universe and the role of the cosmological constant in cosmic evolution.

unscientific
Messages
1,728
Reaction score
13

Homework Statement



(a)Sketch how the contributions change with time
(b)For no cosmological constant, how long will this universe exist?
(c)How far would a photon travel in this metric?
(d)Find particular density ##\rho_E## and scale factor
(e)How would this universe evolve?[/B]
a4rlts.png


Homework Equations

The Attempt at a Solution



Part(a)
[/B]
For dust/matter: ##\rho \propto a^{-3}##. For Curvature: ##\rho \propto a^{-2}##. For Vacuum: ##\rho = const.##.
313sopy.png


In early times, dust dominated. Late times, curvature dominated.Part(b)
For dust: ##a \propto t^{\frac{2}{3}}##. For Curvature: ##a \propto t##. The universe first expands a little then reaches the big crunch where ##\dot a = 0## then starts to contract. In late times, curvature dominates.
I suppose a rough time would be of order ##\propto t_0##.

Part(c)
D_C = \int_0^X \frac{1}{\sqrt{1-kr^2}}
D_C = \frac{1}{\sqrt k} sin^{-1}\left( \sqrt k X \right)
X = \frac{1}{\sqrt k} sin \left( \sqrt k D_C\right)
Furthest distance is simply ##\frac{1}{\sqrt k}##.

Part(d)
Starting with the Raychauduri Equation:
\frac{\ddot a}{a} = -\frac{4\pi G}{3}\left( \rho + \frac{3P}{c^2} \right) + \frac{1}{3} \Lambda c^2 - \frac{kc^2}{a^2}
For a static solution,
0 = -\frac{4\pi G}{3}\left( \rho + \frac{3P}{c^2} \right) + \frac{1}{3} \Lambda c^2 - \frac{kc^2}{a^2}
0 = -\frac{4\pi G}{3} \rho + \frac{1}{3} \Lambda c^2 - \frac{kc^2}{a^2}
0 = -\rho + \frac{\Lambda c^2}{4 \pi G} - \frac{3 kc^2}{4 \pi G a^2}
Thus ##\rho_E = \frac{\Lambda c^2}{4 \pi G}##.

How do I find the scale factor for this density?
 
Physics news on Phys.org
anyone tried part (d) yet? I'm sure my parts (a)-(c) are right.
 
bumpp on part (d)
 
bumpp
 

Similar threads

  • · Replies 0 ·
Replies
0
Views
2K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 18 ·
Replies
18
Views
2K
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
4K
Replies
2
Views
2K