How do I find the solution to this derivative problem?

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To solve the derivative problem involving the functions f and g, the derivative of (1/g^2) is calculated using the chain rule, resulting in -2g(x)^-3 * g'(x). Given the values f(4)=3, f'(4)=-2, g(4)=7, and g'(4)=5, the expression simplifies to -2 * (7)^-3 * 5. Evaluating this at x=4 yields the final result. Clear step-by-step guidance emphasizes the importance of applying the chain rule correctly in derivative problems.
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Homework Statement


Two functions f and g are such that f(4)=3, f prime (4)= -2, g(4)=7, and g prime (4)=5. Determine (1/g^2) prime(4). By "prime" I mean when there is something that looks like a little "1" exponent on the letter.

Please help and give clear step by step explanations. Thanks.


Homework Equations


N/A


The Attempt at a Solution


I know what is the quotient and product rules are, but I have no idea how to approach this question.
 
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Have you learned the chain rule yet?

My hint is: what is the derivative of
\frac{1}{[g(x)]^2}?
 
n!kofeyn said:
Have you learned the chain rule yet?

My hint is: what is the derivative of
\frac{1}{[g(x)]^2}?

Is it -2g(x)^-3 x g(x)?
 
Hint #2:
Chain rule: f(g(x)) = f'(g(x))g'(x)

In this case...
f(g(x)) = g(x)^-2

Soooo...
 
Cuisine123 said:
Is it -2g(x)^-3 x g(x)?

Exactly. Now evaluate your expression at x=4.

Also, don't use x for multiplication. * would work better. :)
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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