How Do I Find Unit Vectors Perpendicular to Given Vectors?

Click For Summary

Homework Help Overview

The problem involves finding unit vectors that are perpendicular to two given vectors, \(\vec{A}=(3,1,-3)\) and \(\vec{B}=(-2,3,4)\). The original poster expresses confusion regarding the requirements of the assignment, particularly in determining the angle between the vectors and understanding part b) of the question.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the dot product to find the angle between the vectors and question the interpretation of part b) regarding finding perpendicular unit vectors. Some suggest reviewing the cross product as a method to find a vector perpendicular to both given vectors.

Discussion Status

Participants are actively engaging with the problem, sharing hints and resources. Some have indicated that they are beginning to understand the concepts involved, while others still express uncertainty about specific aspects of the assignment.

Contextual Notes

The original poster mentions a lack of prior experience with 3D vectors and expresses frustration with the expectations set by their professor. There are references to external resources and textbooks that may provide additional context or clarification.

Pogorz
Messages
15
Reaction score
0

Homework Statement



My prof gave me a homework assignment and i don't really understand how to do the question.

You are give two vectors [tex]\vec{A}[/tex]=(3,1,-3) and[tex]\vec{B}[/tex]=(-2,3,4)
a) Find the angle between the two vectors
b) Find all the unit vectors (if there are more than one) perpendicular to both vectors.

Homework Equations



[tex]\vec{A}[/tex]x[tex]\vec{B}[/tex]=(A[tex]_{y}[/tex]B[tex]_{z}[/tex]-A[tex]_{z}[/tex]B[tex]_{y}[/tex])[tex]\hat{i}[/tex]-etc(don't feel like typing it all out, you guys know what i mean)

The Attempt at a Solution



I drew out graphs (sort of) of the vectors to get a grasp on it. I'm not sure what it's asking for in part b) of the question. And I have NO idea how to find the angles between the lines.
 
Physics news on Phys.org
Hint: [itex]\textbf{A}\cdot\textbf{B}=|\textbf{A}||\textbf{B}|\cos\theta[/itex]...
 
gabbagabbahey said:
Hint: [itex]\textbf{A}\cdot\textbf{B}=|\textbf{A}||\textbf{B}|\cos\theta[/itex]...

just to see if I'm on the right path... (Ax)(Bx) = i, (Ay)(By) = j, (Az)(Bz) = k. i+j+k = [itex]\textbf{A}\cdot\textbf{B}[/itex]?

My calc teacher in high school never did matrices with us, and neither did my phys 30 teacher, first week on uni and my prof expects me to know it so I'm getting the lovely people of the internet to teach me. Does anyone have a site with vector problems that would help me strengthen these skills?
 
Okay, read through unit vectors in my physics textbook. and my calc textbook. and on that site gabba posted. and my class notes. and i still don't understand what part b) is asking me to do.
 
Pogorz@gmail. said:
Okay, read through unit vectors in my physics textbook. and my calc textbook. and on that site gabba posted. and my class notes. and i still don't understand what part b) is asking me to do.

look at the "cross product" section of the given link
 
Well, [itex]\textbf{A}\times\textbf{B}[/itex] will always produce a vector perpendicular to both [itex]\textbf{A}[/itex] and [itex]\textbf{B}[/itex] right?
 
Okay, thanks for the help. I got some answers that do make sense. And I'd just like to point out i have no experience of any 3D vectors before monday, and anything i do know i learned through my textbooks and the internet. So thanks for the patience.
 

Similar threads

Replies
11
Views
2K
Replies
26
Views
3K
  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
5
Views
2K
  • · Replies 20 ·
Replies
20
Views
4K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 14 ·
Replies
14
Views
5K
  • · Replies 0 ·
Replies
0
Views
2K