How Do I Name the Cyclic Isomer of C2H4O?

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Discussion Overview

The discussion revolves around the IUPAC naming of cyclic isomers of C2H4O and C3H6O, specifically focusing on a triangular ring structure for C2H4O and identifying the last isomer of C3H6O. Participants explore various naming conventions and structural representations.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Exploratory

Main Points Raised

  • One participant asks how to name a triangular ring isomer of C2H4O with carbon at two vertices and oxygen at the third.
  • Another participant suggests that the isomer might be ethylene oxide and provides a link for reference.
  • There is a mention of the IUPAC name "oxirane" for ethylene oxide, with a question about systematic naming conventions for such compounds.
  • Participants discuss the identification of 11 isomers of C3H6O, with one participant listing 10 known isomers and seeking assistance for the last one.
  • Two ring structures mentioned include cyclopropanol and two epoxide forms: 1,3-epoxypropane and 1,2-epoxypropane.
  • There is a discussion about the enantiomeric nature of 1,2-epoxypropane, leading to the identification of (R)- and (S)- forms.

Areas of Agreement / Disagreement

Participants express uncertainty about the naming of the cyclic isomer and the completeness of the isomer list for C3H6O. There is no clear consensus on the last isomer or the naming conventions, as multiple viewpoints and suggestions are presented.

Contextual Notes

Participants rely on various naming conventions and structural representations, with some assumptions about the functional groups and isomer types. The discussion does not resolve the uncertainty regarding the last isomer of C3H6O.

Who May Find This Useful

This discussion may be useful for chemistry students or professionals interested in organic chemistry, particularly in the naming and identification of isomers and cyclic compounds.

jmm
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Hey,

How would I name (IUPAC) the isomer of C2H4O that is a triangular ring with C at two vertices and O at the third?

Also, I'm trying to name the 11 isomers of C3H6O. So far I have 10 and I can't seem to get the last one. The ones I have are:

propanal
propan-2-one
prop-2-en-1-ol
prop-1-en-2-ol
(Z)-prop-1-en-1-ol
(E)-prop-1-en-1-ol
methoxyethene
cyclopropanol
and two rings like the one I described above with O at a vertex

I hope those names are right but please tell me if they don't make sense and I'll try another one.

Any help will be really appreciated. Thanks!
 
Last edited:
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nichrome` said:
You mean ethylene oxide?

http://en.wikipedia.org/wiki/Ethylene_oxide <---look at pic :)

And sorry, I can't think of that other isomer you seemed to have covered all the functional groups i could think of :P

Yeah I do mean ethylene oxide. I noticed that the IUPAC name is oxirane. Is there a systematic way of naming these or is it just a compound with an arbitrary name?

The last one's not really a big issue. It was for an assignment I had earlier but the structure of all 11 isomers was kind of irrelevant to the actual question. Thanks for the try though :)

Edit: I just found this, regarding the naming of cyclic ethers:
http://academicearth.org/lectures/cyclic-ethers-and-epoxide-naming
 
jmm said:
Hey,

How would I name (IUPAC) the isomer of C2H4O that is a triangular ring with C at two vertices and O at the third?

Also, I'm trying to name the 11 isomers of C3H6O. So far I have 10 and I can't seem to get the last one. The ones I have are:

(list snipped)
and two rings like the one I described above with O at a vertex

I hope those names are right but please tell me if they don't make sense and I'll try another one.

Any help will be really appreciated. Thanks!

What two ring structures do you have? I can draw three here.
 
I have cyclopropanol and I guess the other two might be called 1,3-epoxypropane and 1,2-epoxypropane.
 
jmm said:
I have cyclopropanol and I guess the other two might be called 1,3-epoxypropane and 1,2-epoxypropane.

OK, look at the 1,2-epoxypropane one, or better make a model of it. Now look at the mirror image...
 
Oh so they're enantiomers? So you'd have (R)-1,2-epoxypropane and (S)-1,2-epoxypropane?
 
Yes, that would be my take on the answer
 
Yeah that makes sense. Thanks for your help.
 

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