How do I solve for the position vector using 2-D vector analysis?

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
6 replies · 2K views
princeton_wu
Messages
5
Reaction score
0

Homework Statement



http://imgur.com/wNusHOw

Homework Equations



I have the solutions and how they did it. THey took the deriv for the velocity vector, and then using t=0 and t=14, they found e=3.5 and f=-0.125

The Attempt at a Solution



I understand the math, but I don't understand why this is correct
1) why did they take the velocity vector?
2) if I plug e and f back into the position vector, and using t=14 i should get θ=0, ie, j-component is 0. But I don't. So what am I doing wrong?
 
Physics news on Phys.org
welcome to pf! :smile:

hi princeton_wu! welcome to pf! :smile:
princeton_wu said:
1) why did they take the velocity vector?

because the graph gives you the direction of the velocity vector
2) if I plug e and f back into the position vector, and using t=14 i should get θ=0, ie, j-component is 0. But I don't.

yes you do …

j-component = e + 2ft = 3.5 - 3.5 = 0 :wink:
 
tiny-tim said:
hi princeton_wu! welcome to pf! :smile:because the graph gives you the direction of the velocity vectoryes you do …

j-component = e + 2ft = 3.5 - 3.5 = 0 :wink:

i mean the r vector; shouldn't the J-component of the r-vector be 0 @ t=14? this way, the angle @ t=14 would be 0.
 
princeton_wu said:
i mean the r vector; shouldn't the J-component of the r-vector be 0 @ t=14? this way, the angle @ t=14 would be 0.

i'm not following your reasoning :confused:

the graph shows that vj = 0 (because θ = 0) at t = 14, it says nothing about r :smile:
 
tiny-tim said:
i'm not following your reasoning :confused:

the graph shows that vj = 0 (because θ = 0) at t = 14, it says nothing about r :smile:

sorry, I'm confused too :-p

If you use t=14 and plug it in the original position vector, shouldn't the J-component of the position vector be 0? Reasoning being that for θ to be 0, the J-component has to be 0?

thanks for your patience tiny tim!
 
(just got up :zzz:)
princeton_wu said:
Reasoning being that for θ to be 0, the J-component has to be 0?

but θ (given in the graph) is stated to be the angle of the velocity vector …

i don't understand what you think that has to do with the position vector :redface:
 
  • Like
Likes   Reactions: 1 person
I mulled over it last night and I finallly got it. My problem stemmed from the fact that I didn't realize that a t vs θ graph is a velocity graph). Thanks Tim! :smile: