How Do I Solve the Wave Equation with Given Initial Data?

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SUMMARY

The discussion centers on solving the wave equation using the method of characteristics, specifically the solution form $u(x,t)=F(x+ct)+G(x-ct)$. The initial conditions provided are $u(x,0)=0$ and ${u}_{t}=\frac{x}{(x^2+1)^2}$. The key conclusion is that setting $t=0$ leads to the relationship $F(x)=-G(x)$, resulting in the expression $u(x,t)=F(x+ct)-F(x-ct)$. Further differentiation and evaluation at $t=0$ yield the derivative $F'(x)=\frac{x}{2c(x^2+1)^2}$, which can be integrated to find the function F.

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cbarker1
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Dear Everybody,

I am confused about how to start with the following problem: using the solution from ex. 3:
$u(x,t)=F(x+ct)+G(x-ct)$

"For data u(x,0)=0 and ${u}_{t}=\frac{x}{(x^2+1)^2}$ where x is from neg. infinity to pos. infinity."

Thanks
Cbarker1
 
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Hi Cbarker1,

Try using the method that Klaas van Aarsen and I discussed with you the other day. Feel free to let me know if there are any issues.
 
Cbarker1 said:
Dear Everybody,

I am confused about how to start with the following problem: using the solution from ex. 3:
$u(x,t)=F(x+ct)+G(x-ct)$

"For data u(x,0)=0 and ${u}_{t}=\frac{x}{(x^2+1)^2}$ where x is from neg. infinity to pos. infinity."

Thanks
Cbarker1

Setting t= 0 in $u(x,t)= F(x+ ct)+ G(x- ct)$ gives $u(x, 0)= F(x)+ G(x)= 0$ so $F(x)= -G(x)$. That is, $u(x,t)= F(x+ ct)- F(x- ct)$. Differentiating that with respect to t, $u_t(x, t)= cF'(x+ ct)+ cF'(x- ct)$. Setting t= 0 in that (I presume you mean "$u_t(x, 0)= \frac{x}{(x^2+1)^2}$) we have $2cF'(x)= \frac{x}{(x^2+1)^2}$ so that $F'(x)= \frac{x}{2c(x^2+ 1)^2}$. Integrate that to find F.
 

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