How Do Ideals Generated by Powers of an Element Relate in Commutative Rings?

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SUMMARY

The discussion focuses on the relationship between ideals generated by powers of an element in commutative rings. Specifically, it establishes that for a commutative ring R with unity, the ideal generated by the elements \((a^m)-1\) and \((a^n)-1\) is equal to the ideal generated by \((a^{gcd(m,n)})-1\). The proof involves applying the polynomial identity \((x-1)(x^{k-1}+x^{k-2}+\ldots+x+1)=x^k-1\) to demonstrate the inclusion of both sides of the equation. This relationship is crucial for understanding the structure of ideals in algebraic contexts.

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joecoz88
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Hello,

Let [a,b] be the ideal generated by a and b.

If R is a commutative ring with unity, let a be in R and m,n be natural numbers.

Show that [ (a^m)-1, (a^n)-1 ] = [ (a^gcd(m,n)) -1 ]


Seems simple but I am having trouble with it. Thanks in advance!
 
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LHS included in RHS:
Let d=gcd(m,n), m=ud, n=vd. Apply the formula
(x-1)(x^(k-1)+x^(k-2)+...+x+1)=x^k-1
to x=a^d, k=u,v.

RHS included in LHS:
Let d=gcd(m,n)=rm-sn with positive r,s and A=a^m, B=a^n
(a^d)-1 = (A^r)-1 - (a^d)((B^s)-1) =
= (A^(r-1)+...+A+1)((a^m)-1) - (a^d)(B^(s-1)+...+B+1)((a^n)-1)
 
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