How Do Kinematics and Impulse Principles Apply in a Two-Particle Pulley System?

[songoku]

Homework Statement

Two particles of masses 8 kg and 5 kg are connected to the two ends of a light inextensible string which passes over a fixed smooth pulley. Initially each of the two particles are held at a position which is 5 m above a horizontal ground. The objects are then released from rest. Assuming that the particles never reach the pulley, and also that the particles do not rebound when thhey strike the ground.

(i) find the tension in the string and the acceleration of each particle
(ii) find the distance above the ground of the point H, the highest point reached by the 5 kg mass
(iii) find the speed with which the system is jerked into motion and the impulse experienced by the string during the jerk.

Homework Equations

F = ma
Kinematics
Impulse = change in momentum
p = mv

The Attempt at a Solution

I'm able to do part (i) and (ii). For part (i), I got T = 800/13 N and a = 30/13 ms^-2

I don't understand how to do the part (iii). What is the meaning of "which the system is jerked into motion"? I think maybe I have to find the speed when it moves for the first time, but no information about time given...

Thanks

 

[rl.bhat]

Find the velocities of masses when 8 kg mass hits the ground.
At that instant T becomes zero. 5 kg mass stops accelerating. That may be the point of jerk. After that 5 kg mass retards with g. You can find distance traveled by it before coming to rest.

 

[songoku]

Hi rl.bhat

Oh, that's the point of jerk. Then to find the impulse on the string, take the initlal velocity as the velocity of point of jerk and final velocity = 0?

Thanks

 

[cena]

Can u solve the question ii/ and iii/ a bit clearly...THx