How Do Magnetic Fields Affect Levitating Conductors and Current-Carrying Wires?

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SUMMARY

The discussion centers on the principles of electromagnetism, specifically regarding the behavior of a current-carrying copper wire in a magnetic field. A 0.120 m long copper wire with a mass of 9.02 g carrying a current of 5.10 A levitates in a uniform magnetic field, leading to the conclusion that the magnetic force (Fm) equals the gravitational force (Fg) when the wire hovers at a constant height. Additionally, it is established that two parallel wires carrying current in opposite directions will repel each other due to the interaction of their magnetic fields, confirmed through the application of the right-hand rule.

PREREQUISITES
  • Understanding of electromagnetic principles, specifically Lorentz force
  • Familiarity with the right-hand rule for determining magnetic forces
  • Basic knowledge of current-carrying conductors and their interactions
  • Concept of gravitational force and its relationship with magnetic force
NEXT STEPS
  • Study the Lorentz force equation in detail, focusing on its applications in different scenarios
  • Learn about the right-hand rule and its implications in electromagnetism
  • Explore the concept of magnetic field strength (B) and its calculation methods
  • Investigate the principles of magnetic field interactions between multiple conductors
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in the practical applications of electromagnetism, particularly in understanding the behavior of conductors in magnetic fields.

Mspike6
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Hi..
I have 2 questions ( simple once i assure you :D) in Electromagntics.

1) ""A 0.120 m long copper wire has mass of 9.02 g and is carrying a current of 5.10 A perpendicular to a uniform magnetic field. This apparatus is placed in a strong magnetic field and the wire is found to levitate. Calculate the magnetic field Strength (B)"

Solution :

I actually solved this one right,
Fm=fg
I L B = Mg
B= mg/I L

What i don't understand is, why do we say that Fm=Fg if the wire Levitate ? i mean... if the why Levitate, it make sense that Fm is bigger (in magnitude) then Fg... why do we equalize them ??


My second questions


"Would two parallel wires carrying a current in opposite directions repel or attract one another?"


I think they would repel. but i don't know why :P




Thank, any help is really appreciated.
 
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As for why |magnetic force| = |gravitational force|-- Simple, if the magnetic force were bigger, the loop would accelerate upwards. Of course, if it did that, it would eventually leave the region of uniform magnetic field. (I think your issue may be with the word 'levitate.' I interpret that as 'hovering at a constant height.')

As for the two wires: If the current is going in opposite directions, the wires would repel. I figured that out by first drawing the wires, then doing the right hand rule to find the magnetic field at the second wire due to the first, then doing the right hand rule again to find the magnetic force on the second wire.

You can also think about it relativistically. An electon in one wire is moving in, say, the positive x direction. The other wire is lorenz contracted, but the electrons in that wire (moving in the negative x direction) are Lorenz contracted more than the stationary protons. The wire appears to have a negative net charge to the electrons in the first wire, and so they repel.
 
Last edited:
Thanks a lot Maxl..

and ya, i thought levitate means that it has a constant V > 0

Thanks
 
Thank you for the great question. I love it when people finish their homework but still have questions!
 

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