How Do Quotient Spaces in Topology Relate to Attachments and Retractions?

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The discussion focuses on the relationship between quotient spaces in topology, specifically the attachment of two spaces X and Y along a closed subset A via a continuous map f. It establishes that if A is a strong deformation retract of X, then Y serves as a deformation retract of the quotient space X∪_fY. Additionally, it confirms that the map f can be extended to a continuous map F:X→Y if and only if Y is a retract of X∪_fY. The participants illustrate these concepts with examples, including punctured discs and their homotopy equivalences.

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  • Understanding of quotient spaces in topology
  • Familiarity with deformation retracts and homotopy
  • Knowledge of continuous maps and equivalence relations
  • Basic concepts of fundamental groups in algebraic topology
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  • Study the properties of strong deformation retracts in topology
  • Learn about the construction and implications of quotient spaces
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Let X,Y be two spaces, A a closed subset of X, f:A--->Y a continuous map. We denote by X\cup_fY the quotient space of the disjoint union X\oplus{Y} by the equivalence relation ~ generated by a ~ f(a) for all a in A. This space is called the attachment of X with Y along A via f.

i) If A is a strong deformation retract of X, show that Y is a deformation retract of X\cup_fY.

ii) The map f is extendable to a continuous map F:X-->Y if and only if Y is a retract of X\cup_fY.

I'm really stuck on this question. If A is a strong deformation retract of X, then we have some homotopy H:X\times[0,1]\rightarrowX where for all x in X, H(x,0) = x. H(x,1) is in A. and for all b in A and all t in [0,1], H(a,t) = a.

But what has that got to do with X\cup_fY?

Are the members of X\cup_fY the equivalence classes where for a~b if one of: a = b, f(a)=f(b), a is in A and b=f(u) in Y.

So we want to come up with a map \varphi:X\cup_fY\rightarrow{Y} where for all y in Y, \varphi(y) = y. :confused:
 
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Things in the attachment are things in X or Y but where we identify an element in A with its image. Example: X=Y= a disc A is the boundary of X and f is an isomorphism onto the boudary of Y. The attachment is then two discs identified along their boundary, ie a sphere.

now imagine X is a punctured disc, so it is strongly homotopic to its boundary, S^1. Then it is clear that the join along the boundary is now a punctured sphere, and that this is homotopy equivalent to the disc Y, and that this homotopy can just be taken by extending the strong homotopy of X to its boundary by making it the identity on Y.
 
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hmm thanks a lot Matt I think I've got it.
 
topology is/was for me very frustrating. the results in it are easily seen to be true but it is always hard to write down the proofs because they are so fiddly. take for instance the proof that the fundamental group is indeed a group (associativity of loops) and independent of base point (in a path connected space). try to think of an easy example. at least you will be able to desribe that so that your teachers understand you understand what is going on.
 

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