How Do Tensions in Upper and Lower Strings Differ in Uniform Circular Motion?

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Homework Help Overview

The problem involves a 4.00 kg object attached to a vertical rod by two strings, rotating in a horizontal circle at a constant speed of 6.00 m/s. The objective is to determine the tensions in the upper and lower strings during this motion.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the tensions in the upper and lower strings, questioning whether they are equal. There is mention of using free body diagrams (FBD) to analyze forces acting on the object.

Discussion Status

Some participants have offered guidance on the need to consider the forces acting on the object, suggesting the use of different symbols for the tensions in the upper and lower strings. There is an ongoing exploration of the direction conventions used in the analysis.

Contextual Notes

Participants note the importance of maintaining consistent sign conventions when analyzing forces. The discussion also highlights the need for clarity regarding the forces acting on the object, particularly in relation to the tensions in the strings and the object's weight.

student 1
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Homework Statement


A 4.00 kg object is attached to a vertical rod by two strings. The object rotates in a horizontal circle at constant speed 6.00m/s. Find the tension in the upper string and the lower string.
View attachment phy2.bmp

Homework Equations


C=2\pir
T=(M)V^2)/r


3. The Attempt at a Solution [
The tension should be easy. Since you have the speed and r. and the mass. Will the tension be the same for both strings though?
 
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student 1 said:

Homework Statement


A 4.00 kg object is attached to a vertical rod by two strings. The object rotates in a horizontal circle at constant speed 6.00m/s. Find the tension in the upper string and the lower string.
View attachment 14466

Homework Equations


C=2\pir
T=(M)V^2)/r


3. The Attempt at a Solution [
The tension should be easy. Since you have the speed and r. and the mass. Will the tension be the same for both strings though?

Although I can't see your attachment I can say that the tension in the two strings, will not, in general be equal. I hope the attachment is a FBD, if it isn't, I suggest that you draw one.
 
Anyone help me?? I know the top string has force of Tcos@-Mg in the y direction and Tsin@ in the x direction. I need help on the bottom string would it be pulling the ball down as well so you would have T+MG for y direction and x direction would be TSin@?
 
student 1 said:
Anyone help me?? I know the top string has force of Tcos@-Mg in the y direction and Tsin@ in the x direction.
Good :approve:
student 1 said:
I need help on the bottom string would it be pulling the ball down as well so you would have T+MG for y direction and x direction would be TSin@?
You need to be careful here. Firstly with the direction, for the top string you have taken up as positive (i.e. the ball's weight is negative), however for the bottom string you have taken down to be positive (i.e. the ball's weight and the tension in the bottom string is positive). You need to chose one convention and stick to it throughout.

Secondly, as I said previously, the tensions in the two strings needn't be equal. Therefore, you need to use different symbols for the tension in the upper and lower string, perhaps T1 and T2, as opposed to simply T.

In addition, instead of considering the string separately, you should consider the forces acting on the ball, which are the tensions of the two strings and it's weight.
 

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