How Do Two Cyclists Traveling Towards Each Other Meet?

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SUMMARY

The problem involves two cyclists traveling towards each other from Vectorville and Scalartown, which are 20.0 km apart. The first cyclist travels at 20.0 km/h, while the second cyclist travels at 15.0 km/h. They meet after 20/35 hours, which equals approximately 34.29 minutes. The meeting point can be calculated by determining the distance each cyclist travels in that time, leading to a meeting point of approximately 14.29 km from Vectorville.

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blooreema
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I tried for a really long time to try to answer this question, but I keep getting weird answers... could someone try and help me out? I know we're supposed to use the substitution method but I don't quite get how...


Vectorville and Scalartown are 20.0 km apart.
A cyclist leaves Vectorville and heads for Scalartown at 20.0 km/h.
A second cyclist leaves Scalartown for Vectorville at exactly the same time at a speed of 15.0 km/h.

a) Where will the two cyclists meet between the two towns?
b) How much time passes before they meet (in minutes)?
 
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I'm not really sure what you mean by the substitution method, if you were to explain what you mean by that maybe I could give you a pointer as to how to calculate the answer that way.

However, the way I would do it would be to realize that the two bikes could be treated as one bike traveling at 35 Km/h for a distance of 20 Km. Using good old speed = distance / time would give you the answer to part b, then you could use that to calculate the answer to part a.
 

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