Two cars moving towards each other - bullets fired

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Isobel
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Homework Statement


This problem-solving question is about a police car chasing criminals.
Two cars are moving in the same direction, parallel (assumed).
One car is moving at 82 km/h.
The other car is moving at 64 km/h.
Bullets are fired from the car moving at 82 km/h towards the car moving at 64 km/h at a rate of 15 bullets per second.
a) what is the spread of the bullets that hit the car?
b) how many bullets hit the car?

Homework Equations


I think I'm supposed to use kinematic equations:
s=ut+0.5*at squared
v squared = u squared + 2as
v = u+at
s= (u+v)/2*t

The Attempt at a Solution


I got this question on an exam and I had no idea how to do it. This is just what I remember of the question.
 
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From the thread title it sounds like one car is behind the other, but from the problem statement it sounds more like the cars are side by side with one overtaking and passing the other. Assuming the latter the spread (or spacing) of the impacts can be found, but to answer (b) the length of the criminal's car would have to be known as observed by @kuruman.

I think we need to await the return of @Isobel for clarification.
 
gneill said:
From the thread title it sounds like one car is behind the other, but from the problem statement it sounds more like the cars are side by side with one overtaking and passing the other. Assuming the latter the spread (or spacing) of the impacts can be found, but to answer (b) the length of the criminal's car would have to be known as observed by @kuruman.

I think we need to await the return of @Isobel for clarification.
The cars are side by side with one overtaking the other.
The length of the criminal's car was not given, which is where I got stuck.
Perhaps you could assume the length of the car and work from there?