Two cars moving towards each other - bullets fired

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Homework Help Overview

This problem involves two cars moving parallel to each other, one at 82 km/h and the other at 64 km/h, with bullets being fired from the faster car towards the slower one. The questions focus on the spread of the bullets that hit the slower car and the total number of bullets that make contact.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the meaning of "spread" in relation to the bullets hitting the car and question the need for the muzzle speed of the bullets. There is also mention of the importance of the length of the criminal's car for determining how many bullets hit it.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem setup and awaiting further clarification on certain parameters, such as the length of the car and the muzzle speed of the bullets. Some participants suggest that the spread of the bullets can be calculated based on relative velocity.

Contextual Notes

There is uncertainty regarding the arrangement of the cars (whether one is behind the other or they are side by side), which affects the interpretation of the problem. Additionally, the length of the criminal's car is not provided, which is a critical piece of information for answering part (b).

Isobel
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Homework Statement


This problem-solving question is about a police car chasing criminals.
Two cars are moving in the same direction, parallel (assumed).
One car is moving at 82 km/h.
The other car is moving at 64 km/h.
Bullets are fired from the car moving at 82 km/h towards the car moving at 64 km/h at a rate of 15 bullets per second.
a) what is the spread of the bullets that hit the car?
b) how many bullets hit the car?

Homework Equations


I think I'm supposed to use kinematic equations:
s=ut+0.5*at squared
v squared = u squared + 2as
v = u+at
s= (u+v)/2*t

The Attempt at a Solution


I got this question on an exam and I had no idea how to do it. This is just what I remember of the question.
 
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Isobel said:
what is the spread of the bullets that hit the car?
Do you mean, at what rate do the bullets hit the other car?
What about the muzzle speed of the bullets, is that known?
 
You also need the length of the car to anwer (b).
 
From the thread title it sounds like one car is behind the other, but from the problem statement it sounds more like the cars are side by side with one overtaking and passing the other. Assuming the latter the spread (or spacing) of the impacts can be found, but to answer (b) the length of the criminal's car would have to be known as observed by @kuruman.

I think we need to await the return of @Isobel for clarification.
 
I haven't done the sums but it might be obvious how many bullets hit the car if the spread is large enough.
 
gneill said:
From the thread title it sounds like one car is behind the other, but from the problem statement it sounds more like the cars are side by side with one overtaking and passing the other. Assuming the latter the spread (or spacing) of the impacts can be found, but to answer (b) the length of the criminal's car would have to be known as observed by @kuruman.

I think we need to await the return of @Isobel for clarification.
The cars are side by side with one overtaking the other.
The length of the criminal's car was not given, which is where I got stuck.
Perhaps you could assume the length of the car and work from there?
 
How about starting with part (a). I think by "spread" is meant the distance between successive bullets that hit the car. Can you find that? Think relative velocity.
 

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