The discussion centers on solving the equation for n in the context of permutations, specifically nP3 = 720. The equation is derived from the formula n!/(n-3)! = 720, leading to the simplified expression n(n-1)(n-2) = 720. Participants suggest factoring 720 into its prime components and hint at testing values around 23 to find the solution. The conversation emphasizes the importance of recognizing factorial relationships and simplifying large numbers through cancellation.
PREREQUISITESMathematicians, educators, students preparing for exams, and anyone interested in combinatorial mathematics and problem-solving techniques.
SOLUTION HINTS:gillgill said:how do u solve for n?
nP3=720...n!/(n-3)!=720...do u just start cancelling?
that will be n(n-1)(n-2)=720...but its such a big number...is there another easier way to do it?
gillgill said:how do u solve for n?
nP3=720...n!/(n-3)!=720...do u just start cancelling?
that will be n(n-1)(n-2)=720...but its such a big number...is there another easier way to do it?