How Do Wave Interference and Velocity Relate in Real-Life Scenarios?

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Homework Help Overview

The discussion revolves around wave interference and its relationship with wave velocity in a real-life scenario involving ocean waves. The original poster describes observing wave patterns created by interference between incoming waves and reflected waves off a concrete breaker.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to determine the wavelength and velocity of the waves based on observations of wave patterns and oscillation periods. Some participants question the interpretation of the period and its implications for calculating wave properties.

Discussion Status

Participants are actively engaging with the problem, providing feedback on the original poster's reasoning. There is acknowledgment of the need to clarify the relationship between period, frequency, and wave speed. Multiple interpretations of the wave behavior are being explored.

Contextual Notes

There is a potential misunderstanding regarding the period and frequency of the waves, which may affect the calculations. The original poster's assumptions about standing wave patterns and node placement are also under discussion.

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Homework Statement


A beach comber walking along the top of a sea wall notices that the waves reflecting off of the concrete breaker are creating a pattern of interference with the original incoming waves. A few meters from the breaker the waves are at maximum oscillation with a time between peak and trough of 2.4 seconds. Exactly 3.2m further to sea, there is virtually no vertical change in the water's motion. What is the length and velocity of the waves?


Homework Equations



v=fxlamda

The Attempt at a Solution


So I'm not sure if I'm completely misinterpreting this but I'm thinking it forms a standing wave pattern and the first node is 3.2m away from the antinode so 3.2m x 4 = a wavelength of 12.8m and then v=(4.)(12.8m)(1/4.8)= 2.7m/s
Did I do it right or am I completely off?
 
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That sounds reasonable to me.

The distance between max and min is 3.2m ... separation of consecutive maxima is 6.4m.
Which would represent a path difference of a single wavelength.
 
Oh wait. 2.4 s is the period not the frequency.
 
That makes a difference yes ;)
You only need to relate the period of the standing wave oscillations to the speed and wavelength of the two traveling waves that make it.
 

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