How Do We Correctly Calculate the Distribution of Bosons Among Energy Levels?

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SUMMARY

The calculation of the distribution of bosons among energy levels with degeneracies is accurately represented by the formula \prod_i \frac{(N_i+g_i-1)!}{N_i!(g_i-1)!}. Initially, the incorrect approach used \prod_i \frac{g_i^{N_i}}{N_i!}, which led to a Boltzmann distribution rather than the correct Bose-Einstein distribution. The error arose from misapplying the indistinguishability of particles and incorrectly dividing by N_i!, which overcounts states in scenarios with degeneracies. Understanding the distinction between these distributions is crucial for accurate calculations in statistical mechanics.

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I want to calculate the number of ways for putting N_1,N_2,N_3,...,N_i,... bosons in energy levels with degeneracies g_1,g_2,g_3,...,g_i,....
The particles are indistinguishable and there can be any number of particles in a state.
The level with degeneracy g_i has N_i particles in it.The first of this N_i particles has g_i states to choose.The second,again has g_i choices and the same for all of them.So there are g_i^{N_i} ways for putting N_i particles in g_i sates.But the particles are indistinguishable so their order is not important and so g_i^{N_i} reduces to \frac{g_i^{N_i}}{N_i!}. So the number of ways for putting N_1,N_2,N_3,...,N_i,... bosons in energy levels with degeneracies g_1,g_2,g_3,...,g_i,... is:
<br /> \prod_i \frac{g_i^{N_i}}{N_i!}<br />

But the above result will give us sth like Boltzmann distribution,not Bose-Einstein's and we know that the answer should be like below:
<br /> \prod_i \frac{(N_i+g_i-1)!}{N_i!(g_i-1)!}<br />

But what is wrong?
In deriving my formula,I assumed only that the particles are indistinguishable and don't follow Pauli's principle,the same assumptions made for bosons.So what was different?
Thanks
 
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Dividing by N_i! you are overcounting states. Take just one state with degeneracy g_1=1 and two bosons.
Obviously dividing by 2! is not correct.
 

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