How do we derive the equilibrium constant formula?

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SUMMARY

The equilibrium constant formula, represented as Kc = [C]^c * [D]^d / [A]^a * [B]^b, is derived from the concentrations of products and reactants in a balanced chemical equation. A specific example provided is the redox reaction: 5Fe²⁺ + MnO₄⁻ + 8H⁺ ⇌ 5Fe³⁺ + Mn²⁺ + 4H₂O, leading to the equilibrium constant K_{redox} = [Fe³⁺]⁵ * [Mn²⁺] / ([Fe²⁺]⁵ * [MnO₄⁻] * [H⁺]⁸). Understanding the relationship between rate constants and equilibrium constants is crucial for a comprehensive grasp of this topic. Resources such as chemical potential derivations and chemistry texts are recommended for further learning.

PREREQUISITES
  • Basic understanding of chemical reactions and stoichiometry
  • Familiarity with the concept of equilibrium in chemistry
  • Knowledge of redox reactions and their components
  • Ability to interpret chemical equations and their coefficients
NEXT STEPS
  • Study the derivation of the equilibrium constant using chemical potentials
  • Learn about the relationship between rate constants and equilibrium constants
  • Explore resources on chemical equilibrium, such as the provided links
  • Review advanced topics in physical chemistry related to equilibrium
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Chemistry students, educators, and professionals seeking to deepen their understanding of chemical equilibrium and the derivation of equilibrium constants.

Cheman
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How do we derive the equilibrium constant formula?

ie: Kc= [C]^c*[D]^d/ [A]^a*^b

Thanks in advance. :smile:
 
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To start with basics: the product of concentrations of ionic species belonging to right side (products) over the product of concentrations of ionic species belonging to the left side (reagents)

Now let me give a real example:

5Fe^{2+}+MnO_4^-+8H^+\leftrightharpoons 5Fe^{3+}+Mn^{2+}+4H_2O

The equilibrium constant may be written like this:

K_{redox}=\frac {[Fe^{3+}]^5\times [Mn^{2+}]}{[Fe^{2+}]^5\times [MnO_4^-] \times [H^+]^8}
 
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The equilibrium constant Kc=[Products]^coeffcient/[Reactants]^coefficients

In words: The equilibrium constant is the concentration of the products raised to the power of the coefficient in front of them of the balanced equation divided by the concentration of all the reactants raised to their coefficients. This is of course the "easy" explanation of an equilibrium consant, you probably don't want to see the P-chem explanation.
 
Gravenewworld, my P-chem really sucks, would you please show it, so that I can learn how to do it by using P-chem?
 
http://www.sdsc.edu/chemdyn/classnotes/equil.html

I have no idea how to use Latex, so it would almost be impossible to write down how it is derived. That website shows how to derive the equilibrium constant for gases which will give you an idea of how it is derived in general. You have to work with chemical potentials etc. to derive the equilibrium constant.
 
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This site may also help http://www2.mcdaniel.edu/Chemistry/ch307.notes/Chemical%20Equilibrium.html
 
Wow, they are very good, even too good for me to nearly impossible to understand them easily :smile: However I will devote my energy to learn the basics in it. Thank you for your interest.
 
Your chemistry text should explain this in simple terms, the easiest way to understand equilibrium constant is in terms of the rate constants. The derivation from the forward and reverse rate constants should be given in your text. It is quite important that you understand the relationship between rate constants and equilibrium constatn.

It seems that they have explained the rest. although it is a bit more complex . You should study this section more in depth.

Chem tr. where did you get the redox example (your first post)?
 
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I have totally made up this one, but it doesn't seem to be wrong...
 

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