How Do We Determine the Minimum of a Potential Function in Physics?

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The discussion focuses on determining the minimum of the potential function V(x) = V0 [(e-2\gammax) - 2e-\gammax)] for a particle of mass m. To find the minimum, the derivative dV(x)/dx = 2*\gammaV0[(e-\gammax) - (e-2\gammax)] is calculated and set to zero. This confirms that a point is a minimum if the derivative at that point equals zero. Additionally, the discussion touches on sketching the graph of the potential function.

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If we have a particle of mass m moving in the presence of the following potential in one dimension:

V(x) = V0 [(e-2[tex]\gamma[/tex]x) - 2e-[tex]\gamma[/tex]x)]

In order to find the minimum of the potential V do we take the derivative with respect to x?



dV(x)/dx = 2*[tex]\gamma[/tex]V0[(e-[tex]\gamma[/tex]x) - (e-2[tex]\gamma[/tex]x)]


Is this how we find the minimum potential of V?

And how do we sketch a graph of V?
 
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A point can only be a minimum of a function if the derivative at that point equals what?
 
zero?
 

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