How do we expand fractions to make their denominators the same for subtraction?

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SUMMARY

This discussion focuses on the process of expanding fractions to achieve a common denominator for subtraction. The fractions involved are $\frac{11}{6}$ and $\frac{7}{9}$, with denominators of $6$ and $9$, respectively. The Least Common Multiple (LCM) of these denominators is $18$. The first fraction is expanded by multiplying by $3$, resulting in $\frac{33}{18}$, while the second fraction is expanded by multiplying by $2$, resulting in $\frac{14}{18}$. This allows for the subtraction to be performed as $\frac{11}{6} - \frac{7}{9} = \frac{19}{18}$.

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  • Ability to perform basic arithmetic operations (addition, subtraction)
  • Familiarity with fraction expansion techniques
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  • Practice expanding fractions with different denominators
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bobisaka
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In step 3, how did the fractions come to multiplying with those particular numbers?

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We expand the fractions in that way so that the two fractions get the same denominator, in order to be able to calculate the subtraction, since it is not possible to subtract fractions with different denominators.

The denominator of the first fraction is $6$ and the of the second one it is $9$. We expand both fractions to make their denominators the same as the least common denominator.

The Least Common Multiple of $6$ and $9$ is $18$. It holds that $6\cdot 3=18$ and $9\cdot 2=18$. Therefore we expand the first fraction by $3$ : $\frac{11}{6}=\frac{11\cdot 3}{6\cdot 3}=\frac{33}{18}$ and the second fraction by $2$: $\frac{7}{9}=\frac{7\cdot 2}{9\cdot 2}=\frac{14}{18}$.

Now we can do the subtraction by subtracting the numerators: $$\frac{11}{6}-\frac{7}{9}=\frac{33}{18}-\frac{14}{18}=\frac{19}{18}$$
 

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