How do we find the equivalent voltage in a parallel circuit?

  • Thread starter Thread starter hsnelect
  • Start date Start date
  • Tags Tags
    Ciruit Voltage
Click For Summary
SUMMARY

The discussion focuses on calculating the equivalent voltage in a parallel circuit using Kirchhoff's rules. Participants emphasize the importance of applying Kirchhoff's current law and suggest assigning potentials to specific points in the circuit. The superposition principle is also mentioned as a method to analyze the circuit by calculating the currents from each voltage source individually. The consensus is that simply adding the voltages will not yield the correct equivalent voltage.

PREREQUISITES
  • Understanding of Kirchhoff's laws, specifically Kirchhoff's current law.
  • Familiarity with circuit analysis techniques, including superposition.
  • Basic knowledge of voltage, current, and resistance relationships.
  • Ability to interpret circuit diagrams and assign potentials to circuit points.
NEXT STEPS
  • Study Kirchhoff's laws in detail, focusing on practical applications in circuit analysis.
  • Learn about the superposition theorem and its application in electrical circuits.
  • Explore methods for calculating equivalent resistance in parallel circuits.
  • Practice solving circuit problems using various voltage sources and resistances.
USEFUL FOR

Students studying electrical engineering, circuit designers, and anyone seeking to deepen their understanding of parallel circuit analysis and voltage calculations.

hsnelect
Messages
7
Reaction score
0

Homework Statement



[PLAIN]http://img600.imageshack.us/img600/7497/prob2.jpg

Homework Equations



I = V / R

The Attempt at a Solution



I tried to add the 3 voltages together but i didn't get a correct answer ..
I guess I'm missing something that has to be with the parallel Circuit or something like that ..
so how do we get the equivalent voltage ??

Thanks!
 
Last edited by a moderator:
Physics news on Phys.org
welcome to pf!

hi hsnelect! welcome to pf! :wink:

you need to apply Kirchhoff's rules …

call the currents I2 I4 and I5

what do you get? :smile:
 
Assign a potential of 0 to the bottom right of the circuit.
Assign a Potential of V to the point where V1 and the 4 and 5 ohm resistances mee

work out the currents through the 3 branches of the circuit.
for example the potential across the 5 ohm resistance is V - V3 so the current through it is [itex](V - V_3)/ 5[/itex]

Now you can apply Kirchhof's current law, and then solve for V. The currents can
then be found with the 3 equations you found worked out above.

I don't think that adding the 3 voltages is going to get you anywhere. It seems you
might mean the the superposition principle: If you calculate the currents with only V1 in the circuit and the other voltage sources replaces by a wire, and calculate the currents through the resistances, and then you repeat this with V2 and V3, you can then sum the 3 currents you found for each resistance to get the current through that resistance with all the voltage sources present. I don't think that's an efficient method here.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
20
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
3
Views
1K
Replies
2
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K