How do YBCO superconductors react with hydrochloric acid?

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SUMMARY

The reaction of YBCO 123 (YBa2Cu3O7-δ) with aqueous hydrochloric acid (HCl) results in the formation of Y3+, Ba2+, Cu2+, and Cu3+ ions, along with chloride ions and water. The balanced chemical equation for this reaction is: YBa2Cu3O7 + 13HCl → YCl3 + 2BaCl2 + 3CuCl2 + 6.5H2O + O2. The metal centers, Y and Ba, remain stable within the oxygen/copper cage during the reaction, while copper is converted into various chloride forms. This information is corroborated by a NASA article detailing related reactions of YBCO superconductors.

PREREQUISITES
  • Understanding of YBCO superconductors, specifically YBa2Cu3O7-δ
  • Knowledge of aqueous hydrochloric acid and its chemical properties
  • Familiarity with stoichiometry and chemical reaction equations
  • Basic concepts of ion formation in chemical reactions
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  • Research the properties and applications of YBCO superconductors
  • Study the effects of hydrochloric acid on various metal oxides
  • Explore the implications of ion formation in superconducting materials
  • Read the NASA article on YBCO reactions for deeper insights
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Chemists, materials scientists, and researchers interested in superconductors and their chemical interactions, particularly those studying YBCO materials and their behavior in acidic environments.

Mayhem
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If we consider YBCO 123, YBa2Cu3O7-δ, what would the expected reaction if dissolved in aqeuous HCl? I have tried to find resources about this online, but the closest I got was related to Cl-containing YBCOs, and not actual reaction stoichiometry.

My intuition tells me the metal centers (Y, Ba) are not immediately affected as they are contained in the oxygen/copper cage. Rather, I'd expect products like copper chloride(s).
 
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Update: It turns out it reacts to form Y3+, Ba2+, Cu2+ and Cu3+ ions as well as chloride and water.
 
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Let our YBCO superconductor have the formula YBa2Cu3O7. Then the reaction with hydrochloric acid solution proceeds according to the following equation:
YBa2Cu3O7 + 13HCl → YCl3 + 2BaCl2 + 3CuCl2 + 6.5H2O + O2.

This and some other reactions of YBCO superconductor are described in the follow NASA article: https://ntrs.nasa.gov/api/citations/19920010156/downloads/19920010156.pdf.
 
Last edited:
Is there a question in there? Or are you just posting a fact?
 
Vanadium 50 said:
Is there a question in there? Or are you just posting a fact?
I just found a suitable article for the question that Mayhem asked.
 
Last edited:
It's true but about 6 months too late.
 
Yeah, I wanted to post my answer 6 months ago but had an issue with logging into account.
 
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