How do YBCO superconductors react with hydrochloric acid?

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Discussion Overview

The discussion centers around the chemical reaction of YBCO (YBa2Cu3O7-δ) superconductors with hydrochloric acid, exploring the expected products and stoichiometry of the reaction. Participants share insights and seek clarification on the nature of the reaction and its implications.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant inquires about the expected reaction of YBCO with aqueous HCl, suggesting that the metal centers may not be immediately affected due to their containment in the oxygen/copper cage.
  • Another participant updates that the reaction produces Y3+, Ba2+, Cu2+, and Cu3+ ions along with chloride and water.
  • A third participant proposes a specific reaction equation for YBCO with hydrochloric acid, detailing the products formed, including various chloride salts and water.
  • Some participants question the clarity of the contributions, asking if they contain a question or are merely stating facts.

Areas of Agreement / Disagreement

There is no consensus on the specifics of the reaction or the clarity of the contributions, as some participants express confusion about the nature of the posts and whether they are seeking information or providing it.

Contextual Notes

Participants reference external sources for further information, but the discussion does not resolve the stoichiometry or the implications of the reaction fully.

Mayhem
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If we consider YBCO 123, YBa2Cu3O7-δ, what would the expected reaction if dissolved in aqeuous HCl? I have tried to find resources about this online, but the closest I got was related to Cl-containing YBCOs, and not actual reaction stoichiometry.

My intuition tells me the metal centers (Y, Ba) are not immediately affected as they are contained in the oxygen/copper cage. Rather, I'd expect products like copper chloride(s).
 
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Update: It turns out it reacts to form Y3+, Ba2+, Cu2+ and Cu3+ ions as well as chloride and water.
 
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Let our YBCO superconductor have the formula YBa2Cu3O7. Then the reaction with hydrochloric acid solution proceeds according to the following equation:
YBa2Cu3O7 + 13HCl → YCl3 + 2BaCl2 + 3CuCl2 + 6.5H2O + O2.

This and some other reactions of YBCO superconductor are described in the follow NASA article: https://ntrs.nasa.gov/api/citations/19920010156/downloads/19920010156.pdf.
 
Last edited:
Is there a question in there? Or are you just posting a fact?
 
Vanadium 50 said:
Is there a question in there? Or are you just posting a fact?
I just found a suitable article for the question that Mayhem asked.
 
Last edited:
It's true but about 6 months too late.
 
Yeah, I wanted to post my answer 6 months ago but had an issue with logging into account.
 
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