How do YBCO superconductors react with hydrochloric acid?

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Mayhem
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If we consider YBCO 123, YBa2Cu3O7-δ, what would the expected reaction if dissolved in aqeuous HCl? I have tried to find resources about this online, but the closest I got was related to Cl-containing YBCOs, and not actual reaction stoichiometry.

My intuition tells me the metal centers (Y, Ba) are not immediately affected as they are contained in the oxygen/copper cage. Rather, I'd expect products like copper chloride(s).
 
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Update: It turns out it reacts to form Y3+, Ba2+, Cu2+ and Cu3+ ions as well as chloride and water.
 
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Let our YBCO superconductor have the formula YBa2Cu3O7. Then the reaction with hydrochloric acid solution proceeds according to the following equation:
YBa2Cu3O7 + 13HCl → YCl3 + 2BaCl2 + 3CuCl2 + 6.5H2O + O2.

This and some other reactions of YBCO superconductor are described in the follow NASA article: https://ntrs.nasa.gov/api/citations/19920010156/downloads/19920010156.pdf.
 
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Vanadium 50 said:
Is there a question in there? Or are you just posting a fact?
I just found a suitable article for the question that Mayhem asked.
 
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It's true but about 6 months too late.
 
Yeah, I wanted to post my answer 6 months ago but had an issue with logging into account.
 
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