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Homework Statement
If a system satisfies the equation \nu^2 {\partial^2 \psi\over \partial x^2}={\partial^2 \psi\over \partial t^2}+a{\partial \psi\over \partial t}-b\sin\left({\pi x \over L}\right)\cos\left({\pi \nu t\over L}\right)
subjected to conditions: \psi(0,t)=\psi(L,t)={\partial \psi(x,0)\over \partial t}=0 and \psi(x,0)=c\sin\left({\pi x\over L}\right),
how might I solve this?
Thanks.
Homework Equations
As above.
The Attempt at a Solution
I can solve the equation \nu^2 {\partial^2 \psi\over \partial x^2}={\partial^2 \psi\over \partial t^2}+a{\partial \psi\over \partial t} by separation of variables. But I don't know how to deal with the b\sin\left({\pi x \over L}\right)\cos\left({\pi \nu t\over L}\right) term. Also, what is the "forced component" of \psi(x,t)?