How Do You Balance Decomposition Equations?

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Discussion Overview

The discussion revolves around balancing decomposition equations, specifically focusing on the decomposition of aluminum oxide (Al2O3). Participants explore the concepts of ionic versus molecular compounds, the role of diatomic elements, and the relationship between charges and subscripts in chemical formulas.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant expresses uncertainty about balancing decomposition equations and suggests that oxygen becomes O2 because it is a diatomic molecule.
  • Another participant corrects the first by stating that aluminum is not a diatomic element and advises determining if aluminum oxide is ionic or molecular.
  • A subsequent reply proposes a balanced equation of 2Al2O3 → 2Al2 + 3O2, indicating a potential misunderstanding of where to place coefficients.
  • One participant explains that Al2O3 dissociates into cations and anions, presenting the equation Al2O3 → 2Al3+ + 3O2-.
  • Another participant questions how this equation balances, leading to a clarification that equal amounts of each element and charge are present on both sides.
  • There is confusion expressed regarding the relationship between charge and subscripts, with one participant attempting to understand how the charge of O2- relates to the subscript of Al.
  • A later reply provides an example involving potassium sulfide to illustrate how to determine subscripts based on ionic charges, suggesting that the positive and negative charges must balance for neutrality.

Areas of Agreement / Disagreement

Participants exhibit a mix of understanding and confusion regarding the balancing of decomposition equations, with no clear consensus reached on the correct approach or interpretation of the concepts involved.

Contextual Notes

Some participants express uncertainty about the role of diatomic elements and the relationship between ionic charges and subscripts, indicating potential gaps in foundational knowledge that may affect their understanding of the topic.

touma
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Ok...I'm not entirely sure how to do decompostion equations (balancing) since i just learned it today but...

Al2O3------> ?

I think that the oxygen becomes an O2because it is a diatomic molecule. That I understand.

Do I have to carry the Al2 over so that the factors end up being 3Al2 + O2...the thing is...that wouldn't work with the beginning of the equation because the first Al would be 4 while the factors Al would be 6..when I say this i mean the final equation would be like...2Al2O3----> 3Al2 + O2

I hope that makes sense! I need this for homework and that is how I figured the problem above...if someone could help me...that'd be amazing!
 
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Nope, try again. Hint: you should start by determining if aluminum oxide is an ionic compound or a molecular compound.

And a side note: aluminum is not a diatomic element. The diatomics are: H2, N2, O2, F2, Cl2, Br2, and I2.
 
would it just be...2Al2O3-----> 2Al2 + 3O2?
 
Last edited:
ohh shoot! i see wut i did! i think i was suppose to put the 3 in front of the O2...not the Al2...i think i did that cause i thought that thre wut affect the oxygen if i put it at the beginning
 
Al2O3 is a ionic compound so it will dissociate into a cation (a metal substance) and an anion (a non-metal substance). This is:

Al2O3 --> 2Al3+ + 3O2-
 
but how does that balance? unless I am totally missing the point
 
It is balanced. You have equal amounts of each element on the reactants and on the products. Also same charge is present on both sides of the equation.
 
ohhh so the charge takes the place of the subscript? but it cant...cause the aluminum has to have a subscript of 2...no...shoot...im confused!
 
If you want a tip the charge of O2- takes the subscript of Al (in absolute value, of course) and the charge of Al3+ takes the subscript of O. But think and try to figure out why.
 
  • #10
yeah so i got that part...that the 2- acts for the Al...is the reason why related to the bonding that occurs? the 3+ from the Al couldn't work with the O cause the O has to be a diatomic molecule?
 
  • #11
Not quite. I'll give you an example...write the formula for potassium sulfide. KxSy

Think about the charges of K and S. K has a 1+ charge and S has a 2- charge. You should've been taught that you can figure that out by looking at the periodic table and counting to see how many electrons it needs to gain or lose to have an electron configuration of a noble gas.

The positive charges and negative charges have to be equal so that the compound is neutral. Thus, x = 2 and y = 1, so the answer would be K2S. Do you see why?

Here's another example, but this one invovles oxygen. Write out the formula for calcium oxide. Ca has a 2+ charge and oxygen has a 2- charge, therefore, it will simply be CaO.

I hope that didn't confuse you at all.
 

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