How Do You Calculate a Boat's Acceleration on a Circular Path?

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SUMMARY

The discussion focuses on calculating a boat's acceleration while traveling along a circular path with a radius of 20 meters. Given a speed of 5 m/s and a rate of increase in speed of 2 m/s², the total acceleration is derived using the formula a = (a(t)² + a(n)²)¹/². The tangential acceleration (a(t)) is confirmed as 2 m/s², while the normal acceleration (a(n)) is calculated as 1.25 m/s², leading to a resultant acceleration of approximately 2.36 m/s². The calculations and methodology presented are accurate and validated by participants in the discussion.

PREREQUISITES
  • Understanding of circular motion dynamics
  • Familiarity with acceleration components: tangential and normal
  • Knowledge of basic physics equations related to motion
  • Ability to perform vector addition of accelerations
NEXT STEPS
  • Study the principles of circular motion in physics
  • Learn about vector addition in acceleration calculations
  • Explore the effects of varying speeds on circular paths
  • Investigate real-world applications of circular motion in marine navigation
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Students studying physics, particularly those focusing on mechanics, as well as educators and professionals involved in marine engineering or navigation who require a solid understanding of motion dynamics in circular paths.

joemama69
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Homework Statement


A boat is traveling along a circular path having a radius of 20m. Determine the magnitude of the boat's acceleration when the speed is v=5m/s and the rate of increase in the speed is v'=2 m/s^2

Homework Equations



a=(a(t)^2+a(n)^2)^1/2

The Attempt at a Solution



I believe the a(t)=2 <--- May be wrong
and the equation for a(n)=v^2 / p which i got 1.25
so i pluged these into the relevant equation to get 2.36 m/s^2 is the magnitude of the boats acceleration
 
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my question is if i did it right or not
 
joemama69 said:
I believe the a(t)=2 <--- May be wrong
and the equation for a(n)=v^2 / p which i got 1.25
so i pluged these into the relevant equation to get 2.36 m/s^2 is the magnitude of the boats acceleration
Sounds good to me.
 

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