How Do You Calculate Acceleration and Travel Distance from Velocity-Time Graphs?

Click For Summary

Homework Help Overview

The problem involves a car's motion along a straight road, characterized by varying speeds and accelerations. It requires analyzing a velocity-time graph to determine the acceleration and time intervals based on given distances and speeds.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the area under the velocity-time graph and the distance traveled. There are attempts to use simultaneous equations to find the unknowns, and questions about how to sketch the graph and interpret the areas.

Discussion Status

Some participants have provided guidance on using the area under the graph to find the required values. There appears to be a productive exchange of ideas, with one participant expressing appreciation for the help received.

Contextual Notes

The problem includes specific constraints such as the total distance from point A to D being 675m and the need to find both acceleration and time intervals, which may influence the approaches discussed.

New2Science
Messages
2
Reaction score
0
As a car passes point A on a straight road, it's speed is 10m/s, the car moves with constant acceleration, a m/s/s, along the road for T seconds until it reaches point B, where it's speed is Vm/s.
The car travels at this speed for a further 10 seconds, when it reaches the point C. From C it travels for a further T seconds with constant acceleration 3a m/s/s until it reaches a speed of 20 m/s at the point D.

Sketch the [t,v] graph for the motion, and show that V=12.5

I had no problem with showing V = 12.5 through a simultaneous equation.

However part B states,
The distance from A to D is 675m, find a and T

Any help will be so very greatly appreciated!
Thanks in advance
New2Science
 
Last edited:
Physics news on Phys.org
The area under the graph of velocity is the distance traveled. The area, as should be obvious from the sketch, is a sum of three simple areas. Together with the equation you used for velocity, you should be able to determine a and T from it.
 
If you can sketch the [t,v] graph for the motion, then you can deduce the answer.
The area under the graph is the distance.
 
Thanks a lot for the help!

I got it now (:

Thanks Again
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
1
Views
3K
Replies
25
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
12
Views
2K
Replies
3
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
5
Views
2K