- #1
losthelp
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Homework Statement
A 0.5 kg block is sliding across a table top with an inital velocity of 0.2 m/s. It slides to rest in a distance of 0.7m. Find the average friction force that retracted its motion.
m=0.5kg
vi=0.2m/s
vf=0
d=0.7m
ff=?
Homework Equations
vavg= vf-vi, then d/vavg= t, then a=vavg/t, then fnet=m*a, bleh that's all i can really think to do now :S
The Attempt at a Solution
vavg= 0-0.2= -0.2
t=d/vavg= .7/-.2= -3.5sec
a= -0.2/-3.5=0.057
fnet= 0.5*0.057=0.0287
:S i have no ide ahow to find average frictional force from this :S