How Do You Calculate Binding Energy with the Weizsacker Formula?

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SUMMARY

The Weizsacker formula for calculating binding energy is defined as B(AZX) = aVA - aAA^2/3 - aC[Z(Z-1)]A^-1/3 - aS[(N-Z)^2]/A + δ. For the isotope Nickel-58 (58Ni), the parameters provided by Enrico Fermi are aV = 14 MeV, aA = 13 MeV, aC = 0.72 MeV, aS = 19 MeV, and δ = 33 MeV · A^-3/4. The discussion highlights the need to accurately plug in these values to compute the surface energy, Coulomb energy, symmetry energy, and total binding energy. A discrepancy regarding the delta term's value was noted, with a reference to an alternative value of 11 MeV x A^-1/2 found on Wikipedia.

PREREQUISITES
  • Understanding of nuclear physics concepts, specifically binding energy calculations.
  • Familiarity with the Weizsacker formula and its parameters.
  • Basic algebra skills for substituting values into equations.
  • Knowledge of isotopes, specifically Nickel-58 (58Ni) and its properties.
NEXT STEPS
  • Research the Weizsacker formula in detail, focusing on its derivation and applications.
  • Learn about the significance of each term in the binding energy equation.
  • Explore the differences between various models of nuclear binding energy, including the liquid drop model.
  • Investigate the implications of different delta term values on binding energy calculations.
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Students and researchers in nuclear physics, educators teaching nuclear structure, and anyone interested in the calculations of nuclear binding energies using the Weizsacker formula.

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Homework Statement


For 58Ni:
B(AZX) = aVA - aAA^2/3 - aC[Z(Z-1)]A^-1/3 - aS[(N-Z)^2]/A + δ.
Using the parameter values given by Enrico Fermi (aV = 14 MeV, aA = 13 MeV, aC = 0.72 MeV, aS = 19 MeV, ∆ = 33 MeV · A-3/4), determine each term in the formula.

Calculate the magnitude of the surface energy.

Determine the magnitude of the Coulomb energy.

What is the magnitude of the symmetry energy?

What is the total binding energy according to the Weizsacker formula?

What is the binding energy of the nucleus using the table of atomic masses ?


The Attempt at a Solution


For Nickel:
A=58
Z=28
N=30

Using the given parameters I think it would be a simple plug in on each term to find the wanted energies. So I am not sure why it won't work.
 
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yes i believe they are just plug ins

i am just curious why is your delta term 33MeV x A^-3/4

i checked wiki it says 11MeV x A^-1/2
 

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