How Do You Calculate Braking Distance Based on Initial Speed and Time?

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Homework Help Overview

The discussion revolves around calculating the braking distance of a car based on its initial speed and the time taken to come to a stop. The specific speeds mentioned are 60 km/h and 90 km/h, with a focus on understanding the appropriate equations of motion to apply in these scenarios.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore which equations of motion are suitable for calculating distance when acceleration is not directly known. There is uncertainty about whether to use simpler distance formulas or more complex ones that account for changing velocity during braking.

Discussion Status

Some participants have provided guidance on identifying relevant equations, suggesting that one of the kinematic equations may not require acceleration. There is ongoing exploration of how to interpret the conditions of the problem, particularly regarding the concept of coming to a "dead stop."

Contextual Notes

Participants note the need to clarify initial and final velocities for different scenarios, as well as the implications of changing speeds on the calculations. There is mention of external resources that may assist in understanding the equations of motion better.

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Homework Statement


1. How much distance does a car cover during this period: from 60 Km/Hr, a car comes to a dead stop in 10 seconds, from the time the brake is applied (answer in m/s)
2. What will be the braking distance if the car travels at 90Km/hour (answer in m/s)

Homework Equations


s = ut + 1/2at^2
v^2 = u^2 + 2as

The Attempt at a Solution


NOTE: What equation is best used for the first question, is it distance=v*t OR one of the complicated distance equations since acceleration needs to be found. I am unsure whether you must retain 60 km/hr as initial velocity to 90 km/hr as final velocity in the 2nd question.
 
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One can't simply use d=vt in this case since the velocity is changing during the braking process.
It will be necessary to use a "complicated distance equation", however, not one of the two you listed since you don't know the acceleration yet. Most likely you have a list of four basic kinematic equations for motion with constant acceleration. Assuming you do, is there one that does not have a(for acceleration) in it?
As for the second part, it resets the initial conditions of the problem. The new initial velocity is 90 km/hr and that must be used.
 
bacon said:
One can't simply use d=vt in this case since the velocity is changing during the braking process.
It will be necessary to use a "complicated distance equation", however, not one of the two you listed since you don't know the acceleration yet. Most likely you have a list of four basic kinematic equations for motion with constant acceleration. Assuming you do, is there one that does not have a(for acceleration) in it?
As for the second part, it resets the initial conditions of the problem. The new initial velocity is 90 km/hr and that must be used.

Thanks for settling the second question but I am still unsure which equation would be best since there is no final velocity and no acceleration.
 
Take a look at this post: https://www.physicsforums.com/showthread.php?t=95426
Click on the link(it's titled "motion_1dim.pdf").
Scroll down to page 11, you will see four equations of motion. There is one that does not contain acceleration. See if that helps you.

"...there is no final velocity...". Reread the question and think of what "...dead stop..." means and how you would assign a value to it.

Hope this helps.
 
bacon said:
Take a look at this post: https://www.physicsforums.com/showthread.php?t=95426
Click on the link(it's titled "motion_1dim.pdf").
Scroll down to page 11, you will see four equations of motion. There is one that does not contain acceleration. See if that helps you.

"...there is no final velocity...". Reread the question and think of what "...dead stop..." means and how you would assign a value to it.

Hope this helps.

I think I have an idea, thanks for the reply
 

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