How Do You Calculate Buoyant Force on an Iceberg?

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SUMMARY

The buoyant force acting on an iceberg can be calculated using the formula for buoyant force, which is equal to the weight of the displaced fluid. Given the iceberg's area of 3.10x104 km2 and a submerged depth of 0.84 km, the volume of the submerged iceberg is determined by multiplying the area by the submerged depth. The density of water is 1.035x103 kg/m3, allowing for the calculation of the buoyant force as the product of the volume of water displaced and the water density.

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Milad_1989
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Homework Statement



Iceberg area: 3.10x10^4 km^2, Flat top and bottom.
Submerged part .84 km.
Water density: 1.035x10^3

what is the buoyant force acting on the iceberg?

Homework Equations



Fb=Fg pf object of subject = P0V0g
PfVfg=Weight of displaced fluid=p0v0g=weight of object
Vu=v0-vf=v0-(p0v0g/pfg)=v0(1-(po/pf)

I have spend now over 2 hours trying to solve this problem, but no success... Can any help me solve it... driving me crazy..
Thanks in advance..
 
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Milad_1989 said:

Homework Statement



Iceberg area: 3.10x10^4 km^2, Flat top and bottom.
Submerged part .84 km.
Water density: 1.035x10^3

what is the buoyant force acting on the iceberg?

Homework Equations



Fb=Fg pf object of subject = P0V0g
PfVfg=Weight of displaced fluid=p0v0g=weight of object
Vu=v0-vf=v0-(p0v0g/pfg)=v0(1-(po/pf)

I have spend now over 2 hours trying to solve this problem, but no success... Can any help me solve it... driving me crazy..
Thanks in advance..

If the area you mentioned is the area of cross section of the iceberg. Assuming that the iceberg has uniform shape, the volume of iceberg submerged= Iceberg area*Submerged part
the volume of water displaced will be=volume of iceberg submerged= Iceberg area*Submerged part

Buoyant force acting on it=Weight of water displaced=Volume of water displaced*density of water

I wonder if it helps!
 
Thanks, I was over-thinking it and i cannot believe it is so simple.
 

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