Buoyant Force and Archimede's principle

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SUMMARY

The discussion focuses on calculating the buoyant force acting on a helium-filled balloon with a radius of 3.15m and a total mass of 15.2kg, using Archimede's principle. The buoyant force (Fb) is determined to be 149.112 N, calculated by multiplying the mass of the balloon by the acceleration due to gravity (g = 9.81 m/s²). The conversation also addresses the acceleration of the balloon upon release, emphasizing the importance of considering the density of the surrounding air (1.28 kg/m³) in the calculations. Participants clarify that the initial tethering of the balloon affects its acceleration.

PREREQUISITES
  • Understanding of Archimede's principle
  • Knowledge of buoyant force calculations
  • Familiarity with free body diagrams (FBD)
  • Basic physics concepts including mass, weight, and acceleration
NEXT STEPS
  • Learn how to apply Archimede's principle in different fluid scenarios
  • Study the effects of varying densities on buoyant force calculations
  • Explore the relationship between pressure and depth in fluids using P = F/A
  • Investigate the dynamics of tethered objects in fluid environments
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Students studying physics, educators teaching fluid mechanics, and anyone interested in understanding buoyancy and its applications in real-world scenarios.

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Homework Statement


A balloon used for a physics experiment has a radius of 3.15m and is filled with helium. The total mass of the balloon is 15.2kg and the density of the surrounding air is 1.28 kg/m3.
a. How much buoyant force is acting on the balloon?
b. When the balloon is released from the ground, what is the acceleration of the balloon?
c. As the balloon rises, what happens to the radius of the balloon? Explain.

Homework Equations


FB = WDis (buoyant force equals weight of the fluid displaced)
Archimede's principle = an immersed object is buoyed up by a force equal to the weight of the fluid it displaces

P = F/A (pressure equals force divided by area)

P2 = P1 + ρgh
P2 = pressure at top
P1 = pressure at bottom
ρ = density
g = gravity
h = depth/height

ρ = m/v (density equals mass divided by volume)

P1 + 1/2 ρV12 + ρgy1 = P2 + 1/2 ρV22 + ρgy2
V = speed
y = height/depth
P = pressure
ρ = density
g = gravity

The Attempt at a Solution


a. [/B]Buoyant force(Fb) = ?
I drew a free body diagram of the balloon, with Fb pointing up, and Wb, weight of the balloon, pointing down.
Summed forces:
ΣFy = may
Fb - Wb = 0 (since acceleration = 0)
Fb = Wb
Fb = Mb(g)
Fb = (15.2 kg)(9.81 m/s2)
Fb = 149.112 N

I'm not sure if this is correct or not? Are there any other forces acting on the balloon that I missed?

b. Acceleration of balloon (ab) = ?

Fb - Wb = ma
a = (Fb - Wb) / m

That's as far as I've gotten with this one - I'm not sure if this is the correct way to go about finding the acceleration. If so, for the m in the equation, would i be using the mass of the balloon?

I feel like there's something I need to add since the density of the air was given in the problem, but I'm not sure where that fits in?

Any help would be great,
thanks!
 
Last edited:
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Did your FBD include the tension in the rope holding the balloon down? It's only because it's initially tethered that it doesn't accelerate. So your equation:

Fb - Wb = 0 (since acceleration = 0)

is not correct.

Use Archimede's principle to calculate the buoyant force. That's where the density of the air comes into play.
 

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