How Do You Calculate Current Density Between Coaxial Cylinders?

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SUMMARY

The discussion focuses on calculating the current density J(r) between two long coaxial metal cylinders with a dielectric material of conductivity sigma and dielectric constant epsilon. The first method presented calculates resistance and derives J(r) as Vo*sigma / (r*ln(r/a)), while the second method incorporates the dielectric constant, resulting in J(r) = sigma*Vo*epsilon / (r*ln(b/a)). The consensus among participants favors the first method for its clarity and correctness, confirming that the current density is indeed a function of the radius and the logarithmic term.

PREREQUISITES
  • Understanding of coaxial cylinder geometry
  • Familiarity with electrical conductivity and dielectric properties
  • Knowledge of Ohm's Law and its applications in cylindrical coordinates
  • Basic concepts of capacitance and resistance in electrical circuits
NEXT STEPS
  • Study the derivation of resistance in cylindrical coordinates
  • Explore the relationship between current density and electric field in conductive materials
  • Learn about the implications of dielectric constants in electrical engineering
  • Investigate the effects of bound charges on current flow in dielectric materials
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Electrical engineers, physics students, and anyone involved in the study of electromagnetism and circuit theory will benefit from this discussion.

RyanP
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Homework Statement


[/B]
Two long, coaxial metal cylinders are separated by a material of conductivity sigma and dielectric constant epsilon. The radius of the inner cylinder is a, the radius of outer cylinder is b, and the length of both is L.

Suppose that the inner conductor is held at a potential Vo with respect to the outer one. What is the current density J(r) between the two?

Homework Equations


J(r) = I/A = sigma*E
C=Q/V
R=s/(A*sigma)

The Attempt at a Solution


First attempt:
I found resistance of the dielectric to be ln(b/a)/(2pi*L*sigma). As a function of radius r, R(r) = ln(r/a)/(2pi*L*sigma).

Current = V/R = Vo / (ln(b/a)/(2piLsigma)) = Vo*2pi*L*sigma / ln(r/a) as a function of r.
Then divide by Area=2pi*L*r to get current density J(r) = Vo*sigma / (r*ln(r/a)). Second attempt:
Vo = Q/C. I found capacitance of the configuration to be 2pi*epsilon_o*L*epsilon / ln(b/a) using the expression for resistance. Then Q = Vo*2pi*L*epsilon*epsilon_o / ln(b/a).
EA = Q/epsilon_o, so E = Vo*epsilon / (r*ln(b/a)). Using J(r) = E*sigma, I get J(r) = sigma*Vo*epsilon / rln(b/a).

The difference in the two is the presence of epsilon (dielectric constant) in the numerator, and b rather than r in the ln term of the denominator. Are either of these approaches correct?
 
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Can bound charges support current flow?
Better stick with method 1.
 
RyanP said:
Current = V/R = Vo / (ln(b/a)/(2piLsigma))
Looks reasonable (but I've not checked it in detail).
RyanP said:
= Vo*2pi*L*sigma / ln(r/a) as a function of r.
That I don't understand. The same total current has to flow through any given radius, no?
 
Ok, maybe instead I'll do J(r) = current (constant) / area (function of r). In this case I just get J(r) = V*sigma/(r*ln(b/a)). Does this sound right?
 
RyanP said:
Ok, maybe instead I'll do J(r) = current (constant) / area (function of r). In this case I just get J(r) = V*sigma/(r*ln(b/a)). Does this sound right?
Sounds right, looks right ... I'm buying!
 
RyanP said:
Ok, maybe instead I'll do J(r) = current (constant) / area (function of r). In this case I just get J(r) = V*sigma/(r*ln(b/a)). Does this sound right?
Looks right to me too.
 

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