How Do You Calculate Current in Different Parts of a Circuit?

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SUMMARY

The discussion focuses on calculating current in a circuit with a 6Ω resistor and a battery. The total resistance is determined using the formula for resistors in series and parallel. The correct approach involves finding the total effective resistance for the parallel section and then combining it with the series resistance. The current through the 6Ω resistor can be calculated once the total current supplied by the battery is accurately determined.

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  • Understanding of Ohm's Law (I = V/R)
  • Knowledge of series and parallel resistor combinations
  • Familiarity with calculating total resistance in circuits
  • Basic circuit analysis techniques
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  • Study the principles of combining resistors in series and parallel circuits
  • Learn how to apply Kirchhoff's laws for current and voltage in circuits
  • Explore the concept of current division in parallel circuits
  • Practice circuit problems involving multiple resistors and power sources
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1. In the circuit of the figure, find the current supplied by the battery.

2. Find the current through the 6[tex]\Omega[/tex] resistor.


Attempt at a solution:

To find the total current supplied by the battery I tried:

[tex]\frac{6*4*2}{6+4+2}[/tex] = 4[tex]\Omega[/tex]

Then I did that resistance in series with the other:

4 + 1 = 5[tex]\Omega[/tex]

Then I figured to find the current I would use I=[tex]\frac{V}{R}[/tex] giving I=[tex]\frac{6}{5}[/tex]. But 6/5 is not the answer for part A apparently. And I have no idea how to get part B.
 
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To find the total current in the circuit provided by the battery, you need the total resistance. Have you learned the equations for combining resistors in series/parallel? You use that to determine the total effective resistance for the parallel section if it was replaced by a single resistor in series. Then combine that value with the 1ohm one in series.

To find the current through a resistor in parallel, you need to know how current is split in parallel circuits.
 

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