How Do You Calculate Diffraction Angles and Slit Width?

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SUMMARY

The discussion focuses on calculating diffraction angles and slit width using the formula dsin(θ) = mλ. Given a monochromatic light wavelength of 441 nm and a distance of 2.16 m from the slit to the screen, the distance between the second minimum and the central maximum is 1.62 cm. The angle of diffraction θ for the second minimum is derived using the approximation sin(θ) ≈ 1.62 cm / 2.16 m, leading to the solution of the problem as confirmed by participants.

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  • Understanding of wave optics principles
  • Familiarity with the concept of diffraction
  • Knowledge of the sine function and its approximations
  • Ability to manipulate equations involving wavelengths and distances
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Homework Statement



Monochromatic light of wavelength 441 nm falls on a narrow slit. on a screen 2.16m away, the distance between the second minimum and the central maximum is 1.62 cm. a) calculate the angle of diffraction thetta of the second minimum. b) find the width of the slit? Rensick Halliday 5th edition. page no. 977

Homework Equations



dsin(theeta) = m lamda(wavelendth)

The Attempt at a Solution

 
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In your formula, since we're talking about the second minimum, m = 2*(2*pi) (since interference happens every deltaS = 2pi*lambda) .
And sin(theta) =~ 1.62cm / 2.16m. From that you should get the results.
 
Thanks . yes i tried it... its solved
 

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