How Do You Calculate the Third Maximum for a Single Slit Diffraction?

[wilson_chem90]

A single slit is illuminated with a helium-neon laser whose wavelength is 633 nm. If the slit width is 2.2 x 10^-5 m, calculate the third maximum in degrees.

Relevant equations:
sinO = (m + 1/2)x(wavelength) / w

The attempt at a solution:
sinO = (m + 1/2)x(wavelength) / w

sinO = (3 + 1/2)x(633 x 10^-9 m) / (2.2 x 10^-5 m)
O = sin inverse0.100704545 m
O = 5.8 degrees

The third maximum is approx. 6 degrees.

Im not completely sure if this is correct.

 

[willem2]

It's correct. sinO = (m + 1/2)x(wavelength) / w is only approximate anyway. only
the minima can be calculated exactly with sinO = (m)x(wavelength) / w

 

[tomcue]

Can anyone confirm?

Your calculation appears to be correct. The third maximum would occur at an angle of approximately 6 degrees, based on the given information. However, it is always important to double check your calculations and make sure you are using the correct equations and units. Additionally, it would be helpful to provide a brief explanation of the steps you took to reach your solution. This will not only help you to better understand the problem, but it will also make your response more clear and informative for others who may be reading it.