How Do You Calculate Direction in Vector Displacement Problems?

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SUMMARY

To calculate the net displacement in vector displacement problems, one must determine both the magnitude and direction. In Jim's case, he walks 100m south, 60m east, and 20m north, resulting in a net displacement of 80m south and 60m east. The magnitude of the net displacement can be calculated using the formula d = √((x2 - x1)² + (y2 - y1)²), which yields a hypotenuse of 100m. The direction can be expressed using trigonometric functions, specifically the arctangent function to find the angle of the hypotenuse relative to the south direction.

PREREQUISITES
  • Understanding of vector displacement concepts
  • Familiarity with the Pythagorean theorem
  • Basic knowledge of trigonometric functions, particularly arctangent
  • Ability to interpret Cartesian coordinates
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  • Study the use of trigonometric functions in determining angles
  • Explore vector addition and subtraction techniques
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Displacement: Magnitude And Direction (urgent)

Homework Statement



Jim walks 100m due south, 60m due east, and then 20m due north. What is his net
displacement (both magnitude and direction)?

Homework Equations



I know how to find the net displacement by the magnitude of the distance...
using the d = sq. rt ( (x2-x1)^2 + (y2-y1)^2 )

but i don't know how to express the direction?

PLEASE HELP!

The Attempt at a Solution

 
Last edited:
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So he goes 80m S and 60m E. If it were a triangle with 80m is a down pointing leg and 60 as a right pointing leg, how would you find the direction the hypotenus goes in?
 
Think vectors.
 

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