How Do You Calculate Energy Supplied in Different Time Intervals of a Circuit?

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SUMMARY

The discussion focuses on calculating energy supplied in a circuit using the functions v(t) = ½ t Volts and i(t) = 12t - 4t² Amps. The instantaneous power p(t) is derived as p(t) = 6t² - 2t³ watts. The energy supplied over specified time intervals (0 < t < 3, 3 < t < 4, and 0 < t < 4) is determined by integrating the power function P(t). Participants clarified that integration should be performed from the lower limit of each interval to the upper limit, specifically from 0 to 3 for the first interval.

PREREQUISITES
  • Understanding of basic electrical engineering concepts, particularly power and energy calculations.
  • Familiarity with calculus, specifically integration techniques.
  • Knowledge of the Passive Sign Convention in circuit analysis.
  • Ability to manipulate polynomial functions in the context of electrical equations.
NEXT STEPS
  • Study integration techniques for calculating energy in electrical circuits.
  • Learn about the Passive Sign Convention and its applications in circuit analysis.
  • Explore advanced power calculations in circuits with varying voltage and current functions.
  • Review polynomial functions and their behavior in limits for better understanding of integration results.
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Electrical engineering students, circuit designers, and anyone involved in analyzing energy consumption in electrical circuits will benefit from this discussion.

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Homework Statement



For the element shown below, v(t) = ½ t Volts and i(t) = 12t-4t2 Amps.

a)Find the instantaneous power p(t) as a function of time.

b)Find the energy supplied (this value can be negative or positive for each range) to the element for the following three time ranges:

0 < t < 3, 3 < t < 4, 0 < t < 4, those are less than or equal to.




Homework Equations



There is a picture of the circuit that show that it satisfies the Passive Sign Convention.

P(t) = V(t) i(t)

w= the integral of P(t)

The Attempt at a Solution



for part a. I multiplied the given V times the i and found p(t) to = 6t^2 - 2t^3 watts.

for part b. I attempted to take the integral of P(t) from the first point listed; 0 < t < 3

I don't understand the integration. Do i integrate from infinitie to 0, then from 0 to 3, and then from 3 to infinitie?? I am so lost at this point.
 
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Just integrate form 0 to 3

EDIT: also if you have infinity in the limits, the polynomial will tend to infinity as t→ inf.
 

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