How Do You Calculate Equivalent Capacitance and Charge in a Complex Circuit?

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SUMMARY

The discussion focuses on calculating the equivalent capacitance and charge in a complex circuit involving five capacitors with specified values. The equivalent capacitance (Ct) is determined using the formula 1/Ct = 1/C1 + 1/C4, resulting in 2uF, and 1/Ct = 1/C2 + 1/C5, yielding 99/20uF. The final equivalent capacitance is calculated as Ct = 379/20uF. The charge over capacitor C5 (Q5) is derived from the relationship Q5 = C5 * V, leading to a charge of approximately 1.895 * 10^-4 uC.

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Homework Statement


Find the equivalent capacitance of the capacitor combination, Ct and the charge over C5:Q5
Vab=10V
C1=3uF
C2=11uF
C3=12uF
C4=6uF
C5=9uF

Homework Equations



1) 1/Ct=1/C1+1/C4 = 2uF
2) 1/Ct= 1/C2+1/C5 = 99/20uF

Parallel:
2+99/20+12=379/20uF

Ct=379/20 uF

Charge over Q5:C5

Im failing at this part:
Q5=C5=V

The Attempt at a Solution


Im failing at this part:
Q5=379/20*10-6= 1.895-4uC
 

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Hi apatuka, welcome to PF.
In the given circuit, the charges on C2 and C5 are the same. The voltage across them is given. Find the charge. Then find Q5:C5
 

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