How Do You Calculate Force from a Two-Dimensional Potential Energy Function?

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To calculate the force from a two-dimensional potential energy function, the force vector is derived from the negative gradient of the potential energy function U. Specifically, for the given potential U = 3x^3 * y - 7x, the force components can be found using partial derivatives: Fx = -∂U/∂x and Fy = -∂U/∂y. The resulting force vector is expressed as F(x,y) = ⟨Fx, Fy⟩. It is clarified that the force vector has both magnitude and direction, and the calculation involves taking partial derivatives rather than integration. Understanding this concept is crucial for accurately determining the force in a two-dimensional context.
Thermon
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Homework Statement


A potential energy function for a two-dimensional force is of the form U = 3x3 * y - 7x.
Find the force that acts at the point (x, y).[/B]

Homework Equations


In a 1-dimensional case:
ΔU = -∫Fx dx
dU = -Fx dx
Fx = -dU/dx

The Attempt at a Solution


I know how to find the force in a 1-dimensional case; it's the gradient at the given x.

But I can't wrap my head around it when there are two variables.

Could it perhaps be the sum of the derivatives; Fx = -(dU/dx + dU/dy)?[/B]
 
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Thermon said:

Homework Statement


A potential energy function for a two-dimensional force is of the form U = 3x3 * y - 7x.
Find the force that acts at the point (x, y).[/B]

Homework Equations


In a 1-dimensional case:
ΔU = -∫Fx dx
dU = -Fx dx
Fx = -dU/dx

The Attempt at a Solution


I know how to find the force in a 1-dimensional case; it's the gradient at the given x.

But I can't wrap my head around it when there are two variables.

Could it perhaps be the sum of the derivatives; Fx = -(dU/dx + dU/dy)?[/B]
The force will be a vector. If ##\phi(x,y)## is a potential for ##\vec F(x,y)## then$$
\vec F(x,y) = \langle \phi_x,\phi_y\rangle$$
 
LCKurtz said:
The force will be a vector. If ##\phi(x,y)## is a potential for ##\vec F(x,y)## then$$
\vec F(x,y) = \langle \phi_x,\phi_y\rangle$$

So it's the combined vector of Vy and Vx? Correct me if I'm wrong, but does that means that the force at (x, y) would be the net vector of the Epot up and downwards against Ekin?
Finding those two would involve finding the integral of both Fx and Fy
 
LCKurtz said:
The force will be a vector. If ##\phi(x,y)## is a potential for ##\vec F(x,y)## then$$
\vec F(x,y) = \langle \phi_x,\phi_y\rangle$$

Thermon said:
So it's the combined vector of Vy and Vx? Correct me if I'm wrong, but does that means that the force at (x, y) would be the net vector of the Epot up and downwards against Ekin?
Finding those two would involve finding the integral of both Fx and Fy

I don't know what you mean by "combined vector" and "net vector" and "upwards and downwards". It is a force vector field having two components or a magnitude and direction. And I don't know what Fx and Fy you are talking about. You get the vector field from the potential by taking the partials of the potential, not integrating, as I gave in the formula above.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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